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Nutka1998 [239]
2 years ago
15

Which of the following equations could be the result of using the comparison method to solve the system shown?

Mathematics
2 answers:
Rufina [12.5K]2 years ago
6 0

Answer:

                            6 -2y =4y + 8

masya89 [10]2 years ago
5 0

Answer:

6-2y=4y+8

since you show x through y

Answer:

The result that is obtained on comparing the system of equations in order to get the solution to the system of equations is:

   6 -2y =4y + 8

Step-by-step explanation:

We are given a system of equations in term of variable x and y as follows:

                                x + 2y = 6 --------(1)

                           x - 4y = 8-------------(2)

From equation (1) we have the value of x in terms of y as:

                          x=6-2y

From equation (2) we have the value of x in terms of y as:

                         x=8+2y

Hence, on equation the above two values of 'x' we obtain:

                         6 - 2y = 4y + 8

ghope this helps

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The annual interest on a $15,000 $ ⁢ 15,000 investment exceeds the interest earned on an $8000 $ ⁢ 8000 investment by $685 $ ⁢ 6
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Answer:

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I = (principal x rate x time) / 100

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I = ( 8000 x R × 1) ÷ 100

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I = 80R. ( eqn 1)

Also, let the annual interest on $15,000 investment be K and the rate be V

Since interest on $15, 000 is greater than that of the $8,000 by $685

K = I + 685

Also rate V is 0.6% higher than R

V = (R + 0.6)%

This the interest on the $15, 000 is expressed as

K = ( 15000 × V × 1) ÷ 100 (eqn 2)

Substitute for K and V in eqn 2

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I + 685 = 15000 (R + 0.6) ÷ 100

I + 685 = 150 (R + 0.6)

Open the bracket

I + 685 = 150R + 15 × 0.6

I + 685 = 150R + 9.

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Substitute eqn 1 into eqn 3

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Collect like terms with R to one side

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V = 10.257 %

Thus the interest rate on the $ 8, 000 investment is 9. 657 % = 9.66%

While the interest rate on the $ 15, 000 investment is 10.257% = 10.26%

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