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IrinaK [193]
3 years ago
10

What is the answer? Brainliest and 13 pointsssssss

Mathematics
1 answer:
vodomira [7]3 years ago
5 0

Answer:

33

Step-by-step explanation:

2x^2 +3y

Let x =3 and y=5

2 *(3)^2 +3(5)

We do exponents first

2 * 9  + 3(5)

Then multiply

18+ 15

Add

33

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URGENT FOR A GRADE DUE BY 4:00 WILL GIVE BRAINLIEST AND RATE GOOD PLEASE PLEASE HELP THX!
eduard
First, find the area of the circle A=pi r^2 = 3.14 (8)^2=200.96 
the radius is half the diameter so r=16/2=8

Second, find the area of the triangle A=(hb)/2=(8*16)/2=64
since the triangle is resting on the diameter of the circle that means the height of the triangle is also the radius of the circle so h=8 and b=16 

Third, subtract the area of the triangle from the area of the circle to find the area of the shaded regions. 
so...
200.96-64=136.96
is the answer. 
  

7 0
4 years ago
Real life examples of mean median and mode​
Cerrena [4.2K]

Answer:

For example, if you wish to find the average grade on a test for your class but one student fell asleep and scored a 0, the mean would show a much lower average because of one low grade, while the median would show how the middle group of students scored.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
if a pharmacy technician makes as error resulting in serious consequences who can be held liable in court for error of negligenc
beks73 [17]

The very pharmacy technician must be held guilty


3 0
3 years ago
Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2
Finger [1]

Answer:

\frac{y}{x^2}=\sin x+\pi

Step-by-step explanation:

Consider linear differential equation \frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)

It's solution is of form y\,I.F=\int I.F\,q(x)\,dx where I.F is integrating factor given by I.F=e^{\int p(x)\,dx}.

Given: \frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x

We can write this equation as \frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x

On comparing this equation with \frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x), we get p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x

I.F = e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}      { formula used: \ln a^b=b\ln a }

we get solution as follows:

\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C

{ formula used: \int \cos x\,dx=\sin x }

Applying condition:y(\pi)=\pi^2

\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C

So, we get solution as :

\frac{y}{x^2}=\sin x+\pi

4 0
4 years ago
Rearrange the formula to make t the subject:<br> S=d/t
Virty [35]

Answer:

t = d/S

Step-by-step explanation:

S = d/t

Cross multiply

S x t = d

Divide both sides by S

S/S x t = d/S

t = d/S

4 0
4 years ago
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