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Arisa [49]
3 years ago
10

What is the magnitude of velocity for a 2,000 kg car possessing 3,000 kg.m/s of momentum?

Physics
1 answer:
yanalaym [24]3 years ago
3 0

Answer:

The product of the mass and the volume is known as momentum.

According to the law of momentum, it is stated that the two or more bodies remain in a constant state unless an external force is applied in an isolated room.

Momentum depends on the following:-

Mass

Velocity

Momentum = MASS \ X \ VOLUMEMomentum=MASS X VOLUME

\begin{gathered}momentum = 3000kgm/s\\\\mass = 2000kg\\\\velocity =\frac{momentum}{mass}\\\\v= \frac{3000}{2000} \\\\v= 1.5m/s\end{gathered}

momentum=3000kgm/s

mass=2000kg

velocity=

mass

momentum

v=

2000

3000

v=1.5m/s

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\frac{di}{dt}  = 7.31 \  A/s

Explanation:

From the question we are told that  

     The  number of turns is  N =  450 \  turns

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       The  position from the center consider is  x =  3.45 cm  =  0.0345 m

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        \int\limits { e } \, dl  =  \mu_o *  N  *  \frac{di}{dt }  *  A

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Where A is the  cross-sectional area of the solenoid which is mathematically represented as

                A =  \pi r ^2

=>      e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  \pi r^2

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          \mu_o  =  4\pi * 10^{-7} \  N/A^2

=>     \frac{di}{dt}  =  \frac{2 *  8.20*10^{-6} *  0.0345  }{ 4\pi * 10^{-7} * 450  * (0.0117)^2}

=>      \frac{di}{dt}  = 7.31 \  A/s

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