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Lapatulllka [165]
3 years ago
7

According to the law of reflection, _____.

Physics
2 answers:
ryzh [129]3 years ago
4 0
<h3><u>Answer;</u></h3>

<em>When a wave meets a boundary, the angle of the reflected wave is equal to the angle of the incident wave</em>

<h3><u>Explanation</u>;</h3>
  • <em><u>Reflection is the property of waves in which the waves bounces back upon meeting or hitting the surface of an object or a boundary.</u></em> It may also refer to the change in the direction of a wave when it meets an interface between two media.
  • Therefore, when a wave such as light waves meets an opaque surface, they will bounce back off the surface.
  • <em><u>The reflection of waves obeys the Laws of reflection such that the angle of reflection is equal to the angle of incident wave.</u></em>
sukhopar [10]3 years ago
4 0
Its when a wave meets a boundary, the angle of the reflected wave is equal to the angle of the incident wave.

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Answer: C

Explanation:

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A 24 resistor, an inductor with a reactance of 12 , and a capacitor with a reactance of 10 are in series across a 60 V 50 Hz sou
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Answer:

A⋅24=24A

12=24A

10=24A

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A 500.0 kg module is attached to a 440.0 kg shuttle craft, which moves at 1050. m/s relative to the stationary main spaceship. T
nika2105 [10]

Answer:

0.955286  j

Explanation:

A 500.0 kg module is attached to a 440.0 kg shuttle craft, which moves at 1050. m/s relative to the stationary main spaceship. Then a small explosion sends the module backward with speed 100.0 m/s relative to the new speed of the shuttle craft. As measured by someone on the main spaceship, by what fraction did the kinetic energy of the module and shuttle craft, Ki, increase because of the explosion?

M=500 kg,  m=440 kg

V=1000 m/s, v = 100 m/s

Let relative speed =Vs

Momentum rule says

(M+m)V=mVs+M(Vs-v)

 940(1000)=500(Vs-100)+440Vs

 940000=500Vs-50000+440Vs

 940Vs=940000+50000

 940Vs=990000

 Vs= 990000/940=1053.19 m/s

So, the module speed = Vs-v=1053.19-100=953.19 m/s

Fractional increase in KE is given by;

Total KE after explosion / He before explosion

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5 0
4 years ago
In the javelin throw at a track-and-field event, the javelin is launched at a speed of 29 m/s at an angle of 36???? above the ho
netineya [11]

Answer:

t = 0.96 s  is the time it takes for the angle to reduce

Explanation:

In the launch of projectiles, the velocity is broken down into its x and y components, the velocity in the x-axis is constant, as there is no acceleration, instead the velocity in the axis and is reduced by the effect of the acceleration of gravity.

We can find Vox for the initial conditions

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  Vox = Vo cos θ

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  Vx = Vox  

The velocity on the x axis is constant

By trigonometry, we find the firing angle

 

  tan θ = Voy/ Vx

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  Vy = 23.5 tan 18

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Now that we have the vertical speed we can find the time

   Vy = I'm going - g t

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   t = (17 - 7.64) /9.8

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Be the time it takes for the angle to reduce

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4 years ago
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Answer:

electricity

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