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Lapatulllka [165]
3 years ago
7

According to the law of reflection, _____.

Physics
2 answers:
ryzh [129]3 years ago
4 0
<h3><u>Answer;</u></h3>

<em>When a wave meets a boundary, the angle of the reflected wave is equal to the angle of the incident wave</em>

<h3><u>Explanation</u>;</h3>
  • <em><u>Reflection is the property of waves in which the waves bounces back upon meeting or hitting the surface of an object or a boundary.</u></em> It may also refer to the change in the direction of a wave when it meets an interface between two media.
  • Therefore, when a wave such as light waves meets an opaque surface, they will bounce back off the surface.
  • <em><u>The reflection of waves obeys the Laws of reflection such that the angle of reflection is equal to the angle of incident wave.</u></em>
sukhopar [10]3 years ago
4 0
Its when a wave meets a boundary, the angle of the reflected wave is equal to the angle of the incident wave.

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Drupady [299]
Power = energy/time=20/4=5.0
6 0
3 years ago
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What do the plastic jars of the air capacitor represent in an electrical capacitor? The parallel conducting plates The source of
miss Akunina [59]

The plastic jars of the air capacitor represent the parallel conducting plates.

<h3>What is Air capacitor?</h3>

Air capacitor is a type of capacitor that uses air as its dielectric. The simplest air capacitors will contain two conductive plates separated by an air gap.

This capacitor stores and releases electricity in the circuit using;

  • air as the electrical source,
  • balloon as the insulator and
  • the plastic jar as the parallel conducting plates.

Thus, the plastic jars of the air capacitor represent the parallel conducting plates.

Learn more about air capacitor here: brainly.com/question/15755974

3 0
2 years ago
Suppose you have two meter sticks, one made of steel and one made of invar (an alloy of iron and nickel), which are the same len
Mekhanik [1.2K]

Answer:

  • The difference in length for steel is 2.46 x 10⁻⁴ m
  • The difference in length for invar is 1.845 x 10⁻⁵ m

Explanation:

Given;

original length of steel, L₁ = 1.00 m

original length of invar, L₁ = 1.00 m

coefficients of volume expansion for steel, \gamma_{st.} =  3.6 × 10⁻⁵ /°C

coefficients of volume expansion for invar, \gamma_{in.} =  2.7 × 10⁻⁶ /°C

temperature rise in both meter stick, θ = 20.5°C

Difference in length, can be calculated as:

L₂ = L₁ (1 + αθ)

L₂  = L₁ + L₁αθ

L₂  - L₁ = L₁αθ

ΔL = L₁αθ

Where;

ΔL is difference in length

α is linear expansivity = \frac{\gamma}{3}

Difference in length, for steel at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{3.6*10^{-5}}{3} = 1.2*10^{-5} /^oC

ΔL  = 1 x 1.2 x 10⁻⁵ x 20.5 = 2.46 x 10⁻⁴ m

Difference in length, for invar at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{2.7*10^{-6}}{3} = 0.9*10^{-6}/^oC

ΔL  = 1 x 0.9 x 10⁻⁶ x 20.5 = 1.845 x 10⁻⁵ m

8 0
3 years ago
Two coaxial conducting cylindrical shells have equal and opposite charges. The inner shell has charge +q and an outer radius a,
Leviafan [203]

Answer:

\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}

Explanation:

As we know that the charge per unit length of the long cylinder is given as

\lambda = \frac{q}{L}

here we know that the electric field between two cylinders is given by

E = \frac{2k\lambda}{r}

now we know that electric potential and electric field is related to each other as

\Delta V = - \int E.dr

\Delta V = -\int_a^b (\frac{2k\lambda}{r})dr

\Delta V = -2k \lambda ln(\frac{b}{a})

\Delta V = \frac{\lambda ln(\frac{b}{a})}{2\pi \epsilon_0}

\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}

7 0
3 years ago
How many forces are acting on a stationary raft floating in a swimming pool A1 B2 or C3
Hitman42 [59]
There are at least two forces on it, and there could be more.

Vertical forces:
-- gravity, directed downward
-- buoyant force, directed upward
These two forces must be exactly equal, so that the net
vertical force on the raft is zero.  Otherwise, it would be
accelerating either up or down.

Horizontal forces:
We know that the net horizontal force on the raft is zero. 
Otherwise, it would be accelerating horizontally.

But we don't know if there are actually no horizontal forces
at all, or a balanced group of horizontal forces, that add up
to a net force of zero.
3 0
3 years ago
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