A particle moves at a constant speed of 34 m/s in a circular path of radius 6.3 m. From this information, what can be calculated
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The area under the standard normal curve between z=0.19 and z=2.18 is,
P(0.19<z<2.18)= 0.4101
<h3>How can we calculate the area under the curve?</h3>To calculate the The area under the standard normal curve between z=0.19 and z=2.18, we are using two things,
<u>Step 1</u>: The formula,
P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)
<u>Step 2</u>: The statistical values of the area under the curve we get from the picture.
Now we put the known values from the picture in the above formula, we get,
P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)
Or, P(0.19<z<2.18)= 0.9854-0.5753
Or, P(0.19<z<2.18)= 0.4101
From the above calculation we can easily conclude that,
The area under the standard normal curve between z=0.19 and z=2.18 is,
P(0.19<z<2.18)= 0.4101
Learn more about the standard normal curve:
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gravitational force is the attraction force of earth on an object which is near the surface of earth
It will not depend on the velocity or acceleration of earth
So it will not change while an object is stationary or it is moving with some acceleration
So here we will say that force will remain the same