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4 years ago

In general, what is true of the alpha star in a constellation?

Physics

1 answer:

horrorfan [7]4 years ago

7 0

It is generally the brightest compared to the other stars in the constellation.

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A beam of light traveling in air strikes a slab of transparent material. The incident beam makes an angle of 40° with the normal

Molodets [167]

Answer:

V = 2.05× 10⁸ m/s

Explanation:

We are given;

The angle of the incidence; i = 40°

Angle of refraction; (r) = 26°

For us to find the speed of light in the material, we'll use Snell's law

From shell's law, we know that;

n = sin i/sin r = speed of light in air/Speed of light in the medium

Now, speed of light in air = 3 × 10⁸ m/s

Lets speed of light in medium be V

Thus, plugging in the relevant values to obtain;

Sin 40°/sin 26° = 3×10⁸/V

Let's make V the subject;

V = 3 × 10⁸× sin 26°/sin 40°

V = 2.05× 10⁸ m/s

7 0

3 years ago

A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its

hram777 [196]

Answer:

The speed is maximum and the acceleration is zero

Explanation:

- The speed of the mass in simple harmonic motion can be found by using the law of conservation of energy. In fact, the total mechanical energy of the mass-spring system is sum of kinetic energy and elastic potential energy:

$E=K+U=\frac{1}{2}mv^2+\frac{1}{2}kx^2$

where

m is the mass

v is the speed

k is the spring constant

x is the displacement

As we can see, when the displacement is zero (x=0), the term representing the kinetic energy is maximum, so v (the speed) is also maximum.

- The acceleration of the mass in simple harmonic motion is proportional to the restoring force acting on the mass, which is given by Hook's law

$a \propto F = -kx$

where

k is the spring constant

x is the displacement

When x = 0, F = 0, so the net force acting on the mass is zero. Therefore, this also means that the acceleration of the mass is also zero: a = 0.

3 0

3 years ago

Read 2 more answers

A 55 kg pole vaulter falls from rest from a height of 5.4 m onto a foam rubber pad. The pole vaulter comes to rest 0.24 s after

AnnZ [28]

Answer:

a) 10.3 m/s

b) 566 N

Explanation:

$v {}^{2} = {u}^{2} + 2as \\ v {}^{2} = 0 {}^{2} + 2(9.81)(5.4) \\ v = 10.3 \: ms {}^{ - 1}$

$force \: = \frac{d(mv)}{dt} \\ = 55(10.293) \\ = 566 \: newtons$

4 0

3 years ago

10%) Problem 7: Water flows through a water hose at a rate of Q1 = 620 cm3/s, the diameter of the hose is d1 = 1.99 cm. A nozzle

Semenov [28]

Answer:

a) $A_1 = \frac{\pi d_1^2}{4}$

Explanation:

a) the cross-sectional area of the hose would be the square of radius times pi. And since the sectional radius is half of its diameter d. We can express the cross-sectional area A1 in term of diameter d1

$A_1 = \pi r_1^2 = \pi (d_1/2)^2 = \frac{\pi d_1^2}{4}$

6 0

3 years ago

Why do you lurch forward in a bus that suddenly slows? why do you lurch backward when it picks up speed? what law applies here?

AveGali [126]

The law applied here is Newton's first law, also known as, law of inertia.
This law states that: A body will retain its state of rest or motion unless acted upon by an external force.

If you are moving and the bus suddenly stops, your body will lurch forward trying to retain its state of motion until it comes to rest and changes its state by the external force acted on it.

If you are at rest and the bus suddenly moves, your body will lurch backwards trying to retain its state of rest and opposing the force of motion until it is forced to change its state by this force.

8 0

3 years ago