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Leya [2.2K]
3 years ago
11

The null and alternative hypotheses are given. Determine whether the hypothesis test is​ left-tailed, right-tailed, or​ two-tail

ed. What parameter is being​ tested? Upper H 0​: mu equals 105 Upper H 1​: mu not equals 105
Mathematics
1 answer:
WINSTONCH [101]3 years ago
8 0

Answer:    Two-tailed test.

Population mean is the parameter which is tested.

Step-by-step explanation:

Given :   H_0: \mu=105

H_1:\mu\neq105

We know that , the alternative hypothesis (H_1) indicates kind of the hypothesis test we need to perform whether ​left-tailed, right-tailed, or​ two-tailed.

Here, the alternative hypothesis (H_1) is two-tailed, so the hypothesis test is a two-tailed test.

Also, the parameter present in the hypothesis is \mu which is a symbol to represent the population mean.

Thus , Population mean is the parameter which is tested.

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Select all the correct answers. Select all the Expressions that are equivalent to the polynomial below. (3x-7)(2x+8)
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Answer:

6x ² - 10x - 56

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(3x -7) (2x +8)

To expand this, each term in the first bracket would multiply the other bracket.

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The sum of three consecutive even number is 120 find the number by solving a lunar equation
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3 0
3 years ago
A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.8 years, and standard deviation of
Finger [1]

Answer:

Step-by-step explanation:

Hello!

The variable is

X: lifespan of an item

This variable has a normal distribution X~N(μ;σ²)

μ= 5.8 years

σ= 1.7 years

The normal distribution is symmetric, centered on μ, asymptotic to -∞ and +∞. The shortest lifespans will be on the left tail of the distribution and the longest lifespans will be on the right tail. You have to determine how many years the 1% of the items with the shortest lifespan will, this is, the value that separates the bottom 1% of the distribution, symbolically:

P(X≤x₀)= 0.01

Where x₀ represents the value of lifespan you were asked for.

To determine this value you have to work using the standard normal distribution. Derived from the normality distribution is the standard normal distribution. Considering a random variable X with normal distribution, mean μ and variance δ², the variable Z =(X-μ)/δ ~N(0;1) is determined.  

The standard normal distribution is tabulated. Any value of any random variable X with normal distribution can be "converted" by subtracting the variable from its mean and dividing it by its standard deviation.

So to calculate each of the asked probabilities, you have to first, "transform" the value of the variable to a value of the standard normal distribution Z, then you use the standard normal tables to reach the corresponding probability.

So under the standard normal distribution you have to determine the Z value that divides the bottom 1% of the distribution from the top 99%

P(Z≤z₀)= 0.01

Using the standard normal table you have to determine the value of z₀ (it is located in the left tail of the distribution so the value is negative)

z₀= -2.33

Now you have to "translate" the value of Z to a value of the variable of interest:

z₀ =( x₀-μ)/δ

(z₀*δ) =x₀-μ

(z₀*δ)+μ=x₀

x₀= (-2.33*1.7)+5.8= 1.839 years

The lifespan that marks the shortest 1% of the distribution is 1.839

I hope this helps!

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