X^2 - 13 x = -36
add 36 to both sides
x^2 - 13x +36 = 0
figure out the factor
(x-4)(x-9) = 0
so (x-4) or (x-9) equals 0
so solution is
x-4=0 add 4 to both sides and get x = 4
x-9=0 add 9 to both sides and get x=9
x={ 4, 9}
A- the length of the side of a square
P = 16
P = 4a → 4a = 16 |:4 → a = 4
The diagonal of the square: d = a√2
therefore d = 4√2
1/10 because you will do it 10 times
Tyler.
3/4 is the highest fraction of the four options.
