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Cloud [144]
3 years ago
5

Somebody pls help me with this question thx

Chemistry
1 answer:
ololo11 [35]3 years ago
4 0

Answer:

cell wall > skeletal system (maybe)

cell membrane > skin (maybe)

nucleus > brain

mitochondria > digestive system

Explanation:

You might be interested in
568 cm3 of chlorine at 25° C will occupy what volume at -25° C while the pressure remains constant?
Vsevolod [243]

Answer:

474.3 cm³

Explanation:

Given data:

Initial volume of chlorine gas = 568 cm³

Initial temperature = 25°C

Final volume = ?

Final temperature =  -25°C

Solution:

Initial temperature = 25°C (25+273 = 297 K)

Final temperature =  -25°C (-25 +273 = 248 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 568 cm³ × 248 K /297 K

V₂ = 140864 cm³.K / 297 K

V₂ = 474.3 cm³

6 0
4 years ago
A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a
svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = 62.364\text{ L. Torr }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0
3 years ago
Which statement is true regarding methane and ammonia?
sukhopar [10]
The options for given question are as follow,

1) Methane molecules show hydrogen bonding. 
<span>2) Ammonia molecules show hydrogen bonding. </span>
<span>3) Methane has stronger hydrogen bonding than ammonia. </span>
<span>4) Both the compounds do not show hydrogen bonding. </span>
<span>5) Both the compounds have strong hydrogen bonding.
</span>
Answer:
            Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).

Explanation:
                   Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
6 0
4 years ago
Read 2 more answers
The graph shows a relationship between volume and temperature. Which of the following statements is true?
Marat540 [252]

Answer:

The graph shows a directly proportional relationship between volume and temperature and represents Charles' Law.

Explanation:

The relation between volume and temperature is given by :

Ideal gas law, PV = nRT

Where

P is pressure

V is volume

R is gas constant

T is temperature

As volume and temperature have direct relationship. Charles law states that there is a direct relationship between volume and temperature. The correct option is (a).

5 0
3 years ago
If an old car burns 0.05 mL oil every mile, How much oil will it burn if driven 100,000 miles? Show your answer in mL and L?.
Irina18 [472]

0.05 * 100000

= 5000ml

= 5L

7 0
3 years ago
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