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vivado [14]
2 years ago
6

How do enzymes function in biological reactions?

Chemistry
1 answer:
Blababa [14]2 years ago
3 0

Answer:

it binds molecules like a chemical bond-breaking

Explanation:

Enzymes perform the critical task of lowering a reaction's activation energy—that is, the amount of energy that must be put in for the reaction to begin. Enzymes work by binding to reactant molecules and holding them in such a way that the chemical bond-breaking and bond-forming processes take place more readily.

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The side chains of amino acids may contain..
salantis [7]

The correct answer is d)all of above

examples for a are tyrosine for b lysine and for c isoleucine

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3 years ago
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a fraction collected during distillation ethanol-water what is the mass of ethanol that is present in this fraction
AURORKA [14]

Answer:

80 kg

Explanation:

because the liquid with high boiling point is going to be collected the first

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1 year ago
Someone help me with question pls
gizmo_the_mogwai [7]

Explanation:

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8 0
2 years ago
The formula of nitrobenzene is c6h5no2. the molecular weight of this compound is __________ amu.
mafiozo [28]

The molecular weight of a given compound would simply the sum of the molar weights of each component.

 

The molar masses of the elements are:

C = 12 amu

H = 1 amu

N = 14 amu

O = 16 amu

where 1 amu = 1 g / mol

 

Since there are 6 C, 5 H, 1 N and 2 O, therefore the total molecular weight is:

molecular weight = 6 (12 amu) + 5 (1 amu) + 1 (14 amu) + 2 (16 amu)

molecular weight = 123 amu

 

Therefore the molecular weight of nitrobenzene is 123 amu or which is exactly equivalent to 123 g / mol.

4 0
3 years ago
A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is
Vlada [557]

Answer:

c=0.127\ J/g^{\circ} C

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

Q=mc\Delta T

c is specific heat of the metal

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C

So, the specific heat of metal is 0.127\ J/g^{\circ} C.

4 0
2 years ago
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