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cluponka [151]
3 years ago
13

13. Which of the following has the highest amount of kinetic energy?

Chemistry
1 answer:
Anni [7]3 years ago
6 0

Answer:

The answer is option 2.

Explanation:

Given that the formula to find kinetic energy is K.E = 1/2×m/v² where v represent the speed of an object. So if the speed increases, kinetic energy also increase.

Therefore, kinetic energy has the highest amount at 60 mph.

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What are the products of the reaction below?:<br> calcium chloride+ silver nitrate
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What are the final materials of a reaction called? Where are they located in an<br> equation?
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Reactants are starting materials and are written on the left-hand side of the equation. Products are the end-result of the reaction and are written on the right-hand side of the equation.

Explanation:

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The atoms of Group B elements _____ electrons when they form ions. options: A.either gain or lose B.gain C.cannot be determined
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The atoms of Group B elements _____ electrons when they form ions .

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D) lose

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An element has five isotopes. Calculate the atomic mass of this element using the information below. Show all your work. Using t
Katena32 [7]

Answer: Sol:-

Data provided in the question is :-

Atomic mass of isotope -1 = 64 amu

Atomic mass of isotope -2 = 66 amu

Atomic mass of isotope -3 = 67 amu

Atomic mass of isotope -4 = 68 amu

Atomic mass of isotope - 5 = 70 amu

Percentage abundace of isotope - 1 = 48.89 %

Percentage abundance of isotope -2 = 27.81 %

Percentage abundance of isotope - 3 = 4.11%

Percentage abundance of isotope-4 = 18.57%

Percentage abundance of isotope - 5 = 0.62 %

Formula used :-

Average atomic mass of an element =[ {(atomic mass of isotope-1 * percentage abundance of isotope-1) + ( atomic mass of isotope-2 * percentage abundance of isotope -2) + ( atomic mass of isotope -3 * percantege abundance of isotope-3 ) + ( atomic mass of isotope-4 * percentage abundance of isotope-4) + (atomic mass of isotope-5 * percentage abundance of isotope-5)} / 100]

Calculation :-

Put all the value in the formula :-

Average atomic mass of an element = [{(64 * 48.89) + (66 * 27.81) + (67 * 4.11) + (68 * 18.57) + (70 * 0.62)} / 100] amu

= [{(3128.96) + (1835.46) +(257.37) + (1262.76) + (43.4)} / 100] amu

= {(6528.04) / 100} amu

= 65.2804 amu

Average atomic mass of an element is = 65.2804 amu

Then this mass is approximatly equal to atomic mass of zinc so this element would be zinc

atomic mass of zinc = 65.38 \approx 65.2804 amu

5 0
2 years ago
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