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Anna [14]
2 years ago
10

Determine the name and formula of a hydrate with the following composition; 32.30%

Chemistry
1 answer:
Maslowich2 years ago
7 0

1. The formula of the hydrate is FePO₄•4H₂O

2. The name of the hydrate is Iron(iii) phosphate tetrahydrate.

1. Determination of the formula of the hydrate

  • H₂O = 32.3%
  • FePO₄ = 67.7%
  • Formula =?

The formula of the hydrate can be obtained as follow:

Divide by their molar mass

H₂O = 32.3 / 18 = 1.794

FePO₄ = 67.7 / 151 = 0.448

Divide by the smallest

H₂O = 1.794 / 0.448 = 4

FePO₄ = 0.448 / 0.448 = 1

Therefore, the formula of the hydrate is FePO₄•4H₂O

The name of the hydrate is Iron(iii) phosphate tetrahydrate

Learn more about empirical formula: brainly.com/question/16143068

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Calculate the density of the items below. (D = M/V)<br> 1) M = 15g V = 5.0ml *
grin007 [14]

Answer:

<h3>The answer is 3.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 15 g

volume = 5 mL

We have

density =  \frac{15}{5}  \\

We have the final answer as

<h3>3.0 g/mL</h3>

Hope this helps you

5 0
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How would these cells appear under a microscope at a higher magnification.
gulaghasi [49]

they would be more detailed? what type of cells though?


5 0
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Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order o
elena-s [515]

The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

1) In SCl2 we have the S-Cl bond

Electronegativity values: S = 2.5, Cl = 3

Difference = 3.0 -2.5 = 0.5

2) In F2 we have the F-F bond

Electronegativity value: F = 4.0

Difference = 4.0-4.0 = 0

3) In CS2 we have the C-S bond

Electronegativity value: C = 2.5, S = 2.5

Difference = 2.5 -2.5 = 0

4) In CF4 we have the C-F bond

Electronegativity values: C = 2.5, F = 4.0

Difference = 4.0 -2.5 = 1.5

5) In BrCl we have the Br-Cl bond

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5 0
3 years ago
Column A 1. Reproduction: Reproduction 2. offspring: offspring 3. gamete: gamete 4. Budding: Budding 5. Binary fission: Binary f
7nadin3 [17]

Answer:

1. Reproduction: One or two parents, organisms make new offspring

2. Offspring: A new living organism

3. Gamete: female and male create mini-me by cell division

4. Budding: Hydra

5. Binary fission: Bacteria

6. Zygote: The original cell after egg cell and sperm cell join

7. Fragmentation/Regeneration: Sea star / Planarian

8. Mitosis: Healling and growth occurs in budding

9. Meiosis: Egg or sperm cell/ specialized cells

Explanation:

1. Reproduction is the process by which organisms make new offspring either sexually (involving two parents) or asexually (involving one parent only).

2. An Offspring is a new living organism

3. A gamete is a mature sexual reproductive cell, as a sperm or egg, that unites with another cell to form a new organism. It formed from female and male parents by cell division known as meiosis

4. Budding is a form of asexual reproduction in which a new offspring grows out from a part of the parent. It occurs in Hydra.

5. Biinary fission is a form of asexual reproduction which involves a separation of the parent into two new offspring. It commonly occurs in Bacteria

6. Zygote is the original cell formed after egg cell and sperm cell fuse.

7. Fragmentation/Regeneration: this is a form of reproduction in which a parent splits into fragments which are then able to develop into new organisms. It occurs in Sea star and Planarians

8. Mitosis is a form of cell division which a cell divides into two identical daughter cells with the same genetic components as the parent cell. It functions in healing and growth as well as in budding

9. Meiosis is a type of cell division that results in the production of sex cells or gametes. The number of chromosomes in the parent cell is halved and four gamete cells are produced. Egg or sperm cell/ specialized cells are produced by meiosis.

5 0
3 years ago
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