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3 years ago

What is the third angle of a right triangle if one of the angles measures 51.

Mathematics

1 answer:

Elodia [21]3 years ago

3 0

Answer:

Step-by-step explanation:

The short answer is 39.

Every triangle has 180 degrees. There are no exceptions to this rule.

Since a triangle has 3 angles, all three together must add up to 180o

A right angle = 90 degrees always.

You are given 51 degrees as your second angle

The third one is x

x + 51 + 90 = 180 Total of three angles must be 180

x + 141 = 180 The left has been added to give 141

x = 180 - 141 Subtract 141 from both sides

x = 39 The third angle = 39

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When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

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