First, we need to get the concentration of [NaH2PO4]:
[NaH2PO4] =( mass / molar mass ) * volume L
when we have mass NaH2PO4 = 6.6 g & molar mass = 120g/mol & V = 0.355 L
So by substitution:
[NaH2PO4] = (6.6g / 120g/mol) * 0.355 L = 0.0195 M
then, we need to get the concentration of [Na2HPO4]:
[Na2HPO4]= (mass / molar mass ) * volume L
So by substitution:
[Na2HPO4] = (8g/ 142g/mol) * 0.355 L = 0.02 M
and when Pka of the 2nd ionization of phosphoric acid = 7.21
So by substitution in the following formula, we can get the PH:
PH = Pka + ㏒[A]/[AH]
∴PH = 7.21 + ㏒[0.02]/[0.0195]
∴ PH = 7.2
I think so, <span> how much of all chemistry is to do with numbers? A lot! So being good at mathematics makes a huge aspect of chemistry so much easier but if you aren't mathematical then you can work at it and become reasonably proficient at it.</span>
We are asked to convert from units of kilometer per second to units of miles per year. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1 mile is equal to 1609 meters and 1000 m is equal to 1 kilometer. Also, we will find that 3600 s is equal to 1 hr, 24 hr is equal to 1 day and 365 days is equal to 1 year. We do the conversion as follows:
3.8 km / s ( 1000 m / 1 km ) ( 1 mile / 1609 meters ) ( 3600 s / 1 hr ) ( 24 hr / 1 day ) ( 365 days / 1 year ) = 74479055.3 miles per year
Answer : The percentage aniline protonated is, 0.0209 %
Explanation :
First we have to calculate the pOH.
Now we have to calculate the hydroxide ion concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![5.68=-\log [OH^-]](https://tex.z-dn.net/?f=5.68%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=2.09\times 10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D2.09%5Ctimes%2010%5E%7B-6%7DM)
The equilibrium chemical reaction will be:
From the reaction we conclude that,
Concentration of 
ion = Concentration of 
ion = 
Now we have to calculate the percentage aniline protonated.
Thus, the percentage aniline protonated is, 0.0209 %
Cloudy skies and precipitation. Rain is normally caused by water vapor within the condensation of the low pressure system.
