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zubka84 [21]
3 years ago
9

There is a bag with only red marbles and blue marbles.The probability of randomly choosing a red marble is59.There are 63 marble

s in total in the bag and each is equally likely to be chosen.Work out how many red marbles there must be.
Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

37

Step-by-step explanation:

59 percent times 63 in total marbles is 37

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WILL GIVE BEST RESPONSE
tino4ka555 [31]
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1, 
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4 0
3 years ago
An independent-measures research study uses a total of 18 participants to compare two treatment conditions. If the results are u
Luba_88 [7]

Answer:

The answer is false

Step-by-step explanation:

In a sample above 30 obs  like this the confidence interval is defined as

X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.

To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level

The significance is obtained:

significance = 1 - confidence level = 1 - 0.9 = 0.10

Degrees of freedom (df) for the inteval are

df = n - 1 = 18 - 1 = 17

So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)

6 0
3 years ago
A. Find the linear approximating polynomial for the following function centered at the given point a. b. Find the quadratic appr
Tema [17]

Answer:

a. p1(x) = 2 - x

b. p2(x) = x² - 3*x + 3

c. p1(0.97) = 1.03; p2(0.97) = 1.0309

Step-by-step explanation:

f(x) = 1/x

f'(x) =  -1/x²

f''(x) = 2/x³

a = 1

a. The linear approximating polynomial is:

p1(x) = f(a) + f'(a)*(x - a)

p1(x) = 1/1 + -1/1² * (x - 1)

p1(x) = 1 - x + 1

p1(x) = 2 - x

b. The quadratic approximating polynomial is:

p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²

p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²

p2(x) = 2 - x + (x - 1)²

p2(x) = 2 - x + x² - 2*x + 1

p2(x) = x² - 3*x + 3

c. approximate 1/0.97 using p1(x)

p1(0.97) = 2 - 0.97 = 1.03

approximate 1/0.97 using p2(x)

p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309

7 0
3 years ago
Round up 6,614,980 to hundreds​
IgorLugansk [536]

well just look at the tens digit and see if it is bigger or smaller than 5, in this case 8>5

so the answer is 6,615,000, it is 000 because 9+1 became a 10

7 0
3 years ago
What is the image of (-9,6) after a dilation by a scale factor of 44 centered at the origin?
vagabundo [1.1K]

Answer:

(- 396, 264 )

Step-by-step explanation:

Since the dilatation is centred at the origin, then multiply each of the coordinates of the point by the scale factor, that is

(- 9, 6 ) → ( (- 9 × 44 ), (6 × 44 ) ) = ( - 396, 264 )

5 0
3 years ago
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