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zubka84 [21]
2 years ago
9

There is a bag with only red marbles and blue marbles.The probability of randomly choosing a red marble is59.There are 63 marble

s in total in the bag and each is equally likely to be chosen.Work out how many red marbles there must be.
Mathematics
1 answer:
Elis [28]2 years ago
7 0

Answer:

37

Step-by-step explanation:

59 percent times 63 in total marbles is 37

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Jeremy is randomly selecting ans outfit to celebrate probability day at his school.He can chose from a green or purple shirt, de
viva [34]
Jeremy can choose his outfit in following ways:
2 ways to select a shirt
2 ways to select a pant
2 ways to select socks
3 ways to select the footwear.

Total number of ways to select the dress = 2 x 2 x 2 x 3 = 24 ways

Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants. The shirt is not specified, so the shirt can be any.

So there are 2 ways to select a shirt, 1 way to select the pant, socks and footwear. So Jeremy can select the desired outfit in 2 ways.

Thus, the probability that Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants = 2/24 = 1/12
8 0
3 years ago
In square YOLA, RL=5x+28 and RO=8X-11
Alexeev081 [22]

Answer:

RL=5x+28 and

RO=8X-11

diagonal of square bisect equally the side

:.5x+28=8x-11

11+28=8x-5x

39=3x

x=39/3=13

<u>RY</u><u>=</u><u>RL</u><u>=</u><u>5</u><u>x</u><u>+</u><u>2</u><u>8</u><u>=</u><u>5</u><u>×</u><u>1</u><u>3</u><u>+</u><u>2</u><u>8</u><u>=</u><u>9</u><u>3</u><u>If the answer is 93, move to </u><u>answer</u><u>.</u>

6 0
2 years ago
O<br> What is the exact circumference of the circle?<br> 3.14<br> 4<br> 7<br> pi
kow [346]
The answer is 4pi because the formula to find the circumference is C = 2 pi r. this question is asking for the terms of pi which means you remove the pi from the formula and solve it with out it. the radius is 2 because of the 2 units on the graph is halfway of the circle. you would just multiply 2 x 2 and get 4. after that you put the pi on the end of the 4. so the answer is C. (4pi)
4 0
2 years ago
An exceptionally bright high school student has applied for two scholarships: a merit scholarship and an athletic scholarship. H
9966 [12]

Answer:

a) 0.70

b) 0.82

Step-by-step explanation:

a)

Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.

P(M)=0.3

P(A)=0.6

P(M∩A)=0.08

P(not getting merit scholarships)=P(M')=?

P(not getting merit scholarships)=1-P(M)

P(not getting merit scholarships)=1-0.3

P(not getting merit scholarships)=0.7

The probability that student not get the merit scholarship is 70%.

b)

P(getting at least one of two scholarships)=P(M or A)=P(M∪A)

P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)

P(getting at least one of two scholarships)=0.3+0.6-0.08

P(getting at least one of two scholarships)=0.9-0.08

P(getting at least one of two scholarships)=0.82

The probability that student gets at least one of two scholarships is 82%.

4 0
3 years ago
At a chocolate store, 70% of the items are dark chocolate and 30% are milk chocolate. Also 20% of the items have nuts and 80% ar
Delvig [45]

Answer:

A. 13%

Step-by-step explanation:

let's suppose there's 1000 bars of chocolate in general

70 % dark = 700 dark choco bars

30 % milk = 300 milk choco bars

20 % have nuts = 200 bars have nuts

80 % don't have nuts = 800 bars don't have nuts

if 90 % of dark chocolate bars don't have nuts, that means 630 dark chocolate bars don't have nuts, but 70 have nuts

200 bars in general have nuts, if only 70 dark chocolate bars have nuts,

200 - 70 = 130

130 = 13%

7 0
3 years ago
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