The third term of the geometric progression will be 1 / 27 with common ratio 2 / 3.
We are given that:
2nd term of geometric progression = 1 / 18
5th term = 4 / 243
Now, we can also write it as:
2nd term = a r ( where r is the common ratio and a is the initial term.)
a r = 1 / 18
5th term = a r⁴
a r⁴ = 4 / 243
Now divide 5th term by 2nd term, we get that:
a r⁴ / a r = ( 4 / 243 ) / ( 1 / 18 )
r³ = 72 / 243
r³ = 8 / 27
r = ∛ (8 / 27)
r = 2 / 3
3rd term = a r²
a r² = a r × r
= 1 / 18 × 2 / 3
3rd term = 1 / 27
Therefore, the third term of the geometric progression will be 1 / 27 with common ratio 2 / 3.
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Your question was incomplete. Please refer the content below:
The 2nd and 5th term of a GP are 1/18 and 4/243 respectively find the 3rd term
thousands period is the answer
let g(x) = x^2+2
let f(x) = 9/x
f(g(x)) is therefore equal to f(x^2 + 2) which is equal to 9/(x^2+2).
Answer:
x1 = 2
x2 = -1/3
Step-by-step explanation:
3x^2-5x-2=0
D=25-4*(-2)*3 = 25 + 24 = 49 --> sqrt 49 = 7
x1 = 5 + 7 / 2*3 = 2
x2 = 5 - 7 / 2*3 = -1/3
