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Irina18 [472]
2 years ago
14

Find mZCBA. A B 49° с

Mathematics
1 answer:
vivado [14]2 years ago
4 0

AB=BC=>\angle A=\angle C=49а\\\angle CBA=180а-\angle A-\angle C=180а-49а-49а=82а

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What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard
Ahat [919]

We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.

We know that area of rectangle is width times length.

To find the area of the given rectangle we will multiply both side lengths as:

\text{Area of rectangle}=\text{Width}\times \text{Length}

\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}

\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2

\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2

\text{Area of rectangle}=\frac{1\times5}{4\times2}\text{ yard}^2

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Therefore, the area of the given rectangle would be \frac{5}{8} square yards.

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3 years ago
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6 0
2 years ago
Classify the triangle based on the side lengths 9, 40 and 41.
artcher [175]

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7 0
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