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marshall27 [118]
3 years ago
7

Parallelogram F C D E is shown. Sides D C and F E are parallel, and sides F C and E D are parallel. The length of C D is 4 r + 1

9, the length of D E is 8 r + 3, and the length of F C is 9 r minus 6.
What is the value of r?



What is the length of segment EF?

units
Mathematics
2 answers:
saw5 [17]3 years ago
8 0

Answer:

r=9

EF= 55

Step-by-step explanation:

igomit [66]3 years ago
3 0

Answer:

r=9

ef=55

Step-by-step explanation:

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D:  r^2 = 4

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Square the radius:  r^2 = 2^2 = 4 (answer)

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4 years ago
In a right triangle, the length of the hypotenuse is 20 inches and the length of one leg is 15 inches. What is the length of the
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3 years ago
Round each decimal to the nearest whole number 2.7 0.7 18.2 6.34 9.8 9.4
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3 years ago
Read 2 more answers
Find the perimeter of the triangle whose vertices are the following, specified points in the plane.
hichkok12 [17]

Given:

The vertices of the triangle are (-10,-3), (1,4) and (-1,7).

To find:

The perimeter of the triangle.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let the vertices of the triangle are A(-10,-3), B(1,4) and C(-1,7).

Using distance formula, we get

AB=\sqrt{(1-(-10))^2+(4-(-3))^2}

AB=\sqrt{(1+10)^2+(4+3)^2}

AB=\sqrt{(11)^2+(7)^2}

AB=\sqrt{121+49}

AB=\sqrt{170}

Similarly,

BC=\sqrt{\left(-1-1\right)^2+\left(7-4\right)^2}=\sqrt{13}

AC=\sqrt{\left(-1-\left(-10\right)\right)^2+\left(7-\left(-3\right)\right)^2} =\sqrt{181}

Now, the perimeter of the triangle is

Perimeter=AB+BC+AC

Perimeter=\sqrt{170}+\sqrt{13}+\sqrt{181}

Perimeter\approx 13.038+3.606+13.454

Perimeter=30.098

Therefore, the perimeter of the triangle is 30.098 units.

8 0
3 years ago
Please can i have some help, just on this question, thank you so much!
Andrew [12]

Answer:

a) 1/2 of 12 = 1/4 of 24

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Step-by-step explanation:

1/2 of 16 is 6, so 6 would be 1/4 of what? 6 x 4 = 24. 6 is 1/4 of 24. The other one is the same. 1/3 of 90 is 30, and 30 is 2/3 of 45.

5 0
2 years ago
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