Foil Multiplication (2n+4)•(4n+7)

Mathematics

2 answers:

ratelena [41]3 years ago

7 0

Step 1: 8n+14n+12n+28

Step 2 Combine like terms: 8n+26+28

Final Answer: 34n+28

kiruha [24]3 years ago

5 0

(2n+4)x(4n+7)

= 8n^2+14x+16n+28
=8n^2+30n+28

that's it :) !!

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$S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784$