Answer:
- -28y^4 - 7y^3 + 62y^2 + 5y - 30
Step-by-step explanation:
<u>Opening the parenthesis and simplifying by combining like terms:</u>
- (6 - y - 4y^2)(-5 + 7y^2) =
- 6(-5) +6(7y^2) - y(-5) -y(7y^2) -4y^2(-5) -4y^2(7y^2) =
- -30 + 42y^2 + 5y - 7y^3 +20y^2 -28y^4 =
- -28y^4 - 7y^3 + 62y^2 + 5y - 30
Answer:
m∠ABE = 27°
Step-by-step explanation:
* Lets look to the figure to solve the problem
- AC is a line
- Ray BF intersects the line AC at B
- Ray BF ⊥ line AC
∴ ∠ABF and ∠CBF are right angles
∴ m∠ABF = m∠CBF = 90°
- Rays BE and BD intersect the line AC at B
∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure
∴ BE is the bisector of angle ABD
∵ m∠EBF = 117°
∵ m∠EBF = m∠ABE + m∠ABF
∵ m∠ABF = 90°
∴ 117° = m∠ABE + 90°
- Subtract 90 from both sides
∴ m∠ABE = 27°
2/5 (-7) 5/2 as you know 2/5 x 5/2 = 1
so 1 x (-7) = -7
so the asnwer is -7
