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2 years ago

Someone plz help e with this math question and quickly

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

6 0

To solve this problem, work out the problem normally as if the "≥" is "=".

3.1v - 1.4 ≥ 1.3v + 6.7

-1.3v -1.3v

________________

1.8v - 1.4 ≥ 6.7

+1.4 +1.4

________________

1.8v ≥ 8.1

___ ___

1.8 1.8

v ≥ 4.5, is the answer.

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A dolphin in an aquarium is 12 feet long. A scale model of the dolphin is 3.5 inches long. What is the scale factor of the mode?

polet [3.4K]

Assuming the life sized dolphin is 12 ft long, what we want to know is what factor do you multiply 12 ft by to get 3.5 inches so converting this to an equation gives: 12*f=3.5 solving for f gives f=3.5/12=.29166...The units on the factor are inches/foot.

So to get the size if anything linear in the small scale you just multiply it's dimension in the full scale by f.

3 0

3 years ago

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

You invest $4000 in an account at 6.5% per year simple interest. How much will you have in the account at the beginning of the 9

aleksandrvk [35]

Answer:

$6340

Step-by-step explanation:

First figure out what 6.5% of 4000 is by multiplying not dividing because dividing will give you a way bigger number.

4000 x 6.5%=260

260 x 9=2340

2340+4000=6340

8 0

3 years ago

Find the measure of the indicated angle to the nearest degree

aleksandrvk [35]

Tan^-1 x (2/3) = 34°

7 0

3 years ago

Jennifer wants to convert 7.85 meters to centimeters but she does not have paper pencil or calculator describe a method she can

lilavasa [31]

She can move the decemal place 2 places to the right because a centimeter is 100 times smaller than a meter. so it would be 785 centimeters

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8 0

3 years ago

Read 2 more answers