Let the tickets be x and the snacks be y.
2x + 3y = 25 .... equation(1) *3 => 6x+9y = 75... (3)
3x + 4y = 35 ....(2) *2 => 6x + 8y= 70....(4)
on (3) - (4)
we get,
6x + 9y = 75
6x + 8y = 70
(-) (-) (-)
___________
y = 5
on putting value of y in (1),
2x + 3*5 = 25
=>2x= 25-15 => 2x = 10 =>x= 10/2 => x= 5
<span>hence , a movie ticket is $5 as well as a snack is $5</span>
Answer:
Yes, 5 is a rational number.
Answer:
c
Step-by-step explanation:
I think so
Answer:
The perpendicular bisector of BC
Step-by-step explanation:
Answer:
The least common multiple is 2y^2 - 50.
Step-by-step explanation:
Least common multiple means the lowest thing you can multiply them both to. For example, the LCM of 2 and 4 is 2, because 2*2 = 4 and 4*1 = 4.
First, factor 2y^2 - 50.
2 (y^2 - 25)
2 (y - 5)(y + 5)
Looks like if we wanted to get 2y^2 - 50 starting with y - 5, we'd have to multiply it by 2(y + 5).
2y^2 - 50 * 1 = 2y^2 - 50
y - 5 * 2(y + 5) = 2y^2 - 50
<u>So their least common multiple is 2y^2 - 50.</u>