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dsp73
2 years ago
8

Hey guys can anyone help me find the missing side length pls and ty

Mathematics
2 answers:
Tcecarenko [31]2 years ago
5 0

\bold{\huge{\green{\underline{ Solution}}}}

\bold{\underline{ Given :- }}

  • <u>We </u><u>have </u><u>given </u><u>a</u><u> </u><u>right</u><u> </u><u>angled </u><u>triangle </u><u>whose </u><u>values </u><u>are </u><u>m</u><u>, </u><u> </u><u>n </u><u>and </u><u>2</u><u> </u>

\bold{\underline{ To \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>m </u><u>and </u><u>n</u>

\bold{\underline{ Let's \: Begin :- }}

<u>In </u><u>the </u><u>given </u><u>right </u><u>angled </u><u>triangle</u><u>, </u><u>we </u><u>have </u>

  • Perpendicular height = n units
  • Base = 2 units
  • Hypotenuse = m units

<u>Now</u><u>, </u><u> </u><u>By </u><u>using </u><u>trigonometric </u><u>ratios </u>

\bold{\pink{ Sin Φ = }}{\bold{\pink{\frac{Perpendicular }{Hypotenuse}}}}

\bold{\red{ Cos Φ = }}{\bold{\red{\frac{Base}{Hypotenuse }}}}

\bold{\blue { tan Φ = }}{\bold{\blue{\frac{Perpendicular }{Base }}}}

<u>According </u><u>to </u><u>the </u><u>question </u><u>:</u><u>-</u>

\bold{ Cos \: 45° = }{\bold{\frac{2}{m}}}

\bold{ 1/√2= }{\bold{\frac{2}{m}}}

\bold{\red{ m = 2√2 \: units }}

  • <u>We </u><u>know </u><u>that </u><u>,</u><u> </u><u>Sum </u><u>of </u><u>Angles</u><u> </u><u>of </u><u>triangle </u><u>is </u><u>1</u><u>8</u><u>0</u><u>°</u><u> </u><u>.</u>

<u>Therefore</u><u>, </u>

Let the unknown angle be x

\sf{ 45° + x + 90° = 180° }

\sf{ x = 180° - 135 °  }

\sf{ x = 45°   }

<u>Now</u><u>, </u>

\bold{ Cos \: x° = }{\bold{\frac{n}{2√2}}}

\bold{ Cos \: 45° = }{\bold{\frac{n}{2√2}}}

\bold{ 1/√2= }{\bold{\frac{n}{2√2}}}

\bold { n = 2√2/√2  }

\bold{\red{ n = 2\: units }}

Thus, The value of m = 2√2 and n = 2

\sf{\blue{ Hence, \: option \: D \: is \: Correct }}

seraphim [82]2 years ago
3 0
Sense you have your answer already….

According to all known laws of aviation, there is no way a bee should be able to fly. Its wings are too small to get its fat little body off the ground. The bee, of course, flies anyway because bees don't care what humans think is impossible.

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Liono4ka [1.6K]

Answer:

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Step-by-step explanation:

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3 years ago
Find the sum or difference<br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B10%7D%20-%20%20%5Cfrac%7B3%7D%7B10%7D%20
Paraphin [41]

Answer:

0.2

Step-by-step explanation:

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3 years ago
Please please please tell the answer​
OlgaM077 [116]

Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Can someone help me...
lukranit [14]

Answer:

48.3 cm^2

Step-by-step explanation:

The area of the enclosing square is that of a square 15 cm on a side, so is ...

square area = (15 cm)^2 = 225 cm^2

The white area is that of a quarter-circle of radius 15 cm, so that area is ...

quarter-circle area = (1/4)πr^2 = (π/4)·(15 cm)^2 = 56.25π cm^2 ≈ 176.7 cm^2

Then the yellow area is the difference ...

yellow area = square area - quarter-circle area

= (225 cm^2) - (176.7 cm^2)

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4 0
3 years ago
An experimental population of fruit flies increases according to the law of exponential growth. There were 60 flies after the 2n
Mice21 [21]

Answer:

There were 10 flies originally

Step-by-step explanation:

Since we have an exponential growth, we will be having a constant percentage of increase and we can set up the increase at any day using the following equation;

V = I(1+r)^d

where V is the number of flies on a particular day

I is the initial number of flies

r is the constant increase in percentage

and d is the number of days.

So we have for the second day;

60 = I(1+r)^2 ••••••(i)

For the fourth day, we have;

360 = I(1+r)^4 ••••••••(ii)

divide equation ii by i; we have;

360/60 = (1+r)^4/(1+r)^2

6 = (1+r)^2

(√6)^2 = (1+r)^2

1 + r = √6

r = √6 - 1

So we can substitute the value of r in any of the equations to get I which is the initial number of flies

Let’s use equation 1

60 = I(1 + r)^2

60 = I(1 + √6 -1)^2

60 = I(√6)^2

60 = 6I

I = 60/6

I = 10 flies

3 0
3 years ago
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