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Anarel [89]
2 years ago
13

Compare each patient's cdna sequence to the wild-type cdna sequence. Each patient has one nucleotide-pair substitution mutation.

At which nucleotide location is the mutation found for each patient?.
Biology
1 answer:
Lera25 [3.4K]2 years ago
3 0

The mutation is a change in the nucleotidic sequence. In the exposed example, Patient 1: nucleotide 143, T<u>T</u>C⇒T<u>G</u>C. Patient 2: nucleotide 143, T<u>T</u>C⇒T<u>C</u>C. Patient 3: nucleotide 147, TT<u>C</u> ⇒ TT<u>G</u>.

<h3>What is a mutation?</h3>

A mutation is a change or alteration in DNI sequences that introduce new variants.

Many of these are eliminated, but some of them might succeed and be incorporated into each individual.

These mutations are the ones that have been selected by natural selection.

<h3>Solving the problem</h3>

We know that each sequence initiates with nucleotide number 103 and ends in nucleotide 162.

So first, we will number the nucleotides, from 103 to 162. Each nucleotide has a number in increasing order.

Now, we will identify the mutations in each of the strands by comparing them with the wild-type sequence. The mutation occurs in one of the nucleotides, so we must look for the change in the bases.

Finally, we will identify the nucleotide location of each mutation.

                   nucleotide                 wild-type                mutated

<u>                       location                 nucleotide              nucleotide      </u><u>           </u>

Patient 1            143                         TTC                         TGC

Patient 2           143                         TTC                         TCC

<u>Patient 3           147                          TTC                        TTG                         </u>

<u />

In the attached files you will find an image for a better understanding.

You will learn more about mutations at

brainly.com/question/4347425

brainly.com/question/17914937

 

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