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2 years ago

Find the cosine of ∠J.

Mathematics

1 answer:

nirvana33 [79]2 years ago

3 0

Answer:

$\cos = \frac{base}{hypotenuse} = \\ \cos(j) = \frac{ \sqrt{29} }{ \sqrt{94} } = \sqrt{ \frac{29}{94} } \\ answer = \sqrt{ \frac{29}{94} }$

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What is the difference of the polynomials [m²n²-7]-(mn+4)

AleksAgata [21]

You can do addition and substraction operations with polynomials similarly as with simple real numbers.

First of all you have to open brackets and then you can add numbers (-7-4=-11). Then the result is following:
$(m^2n^2-7)-(mn+4) =m^2n^2-7-mn-4=m^2n^2-mn-11$

5 0

3 years ago

Which equation best matches the graph shown below ?

zubka84 [21]

Answer is too right
You know the y intercept is -4 so it’s gotta be on of the top 2. Then I plugged in x=1 and it’s just shy of 6 for the one in the top right which matches the graph.

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3 years ago

An ice cream store sells 28 flavors of ice cream. Determine the number of 4 dip sundaes.

weeeeeb [17]

Answer:

$20,475\ ways$

Step-by-step explanation:

we know that

<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we will use the formula

$C(n,r)=\frac{n!}{r!(n-r)!}$

where

n represents the total number of items

r represents the number of items being chosen at a time.

In this problem

$n=28\\r=4$

substitute

$C(28,4)=\frac{28!}{4!(28-4)!}\\\\C(28,4)=\frac{28!}{4!(24)!}$

simplify

$C(28,4)=\frac{(28)(27)(26)(25)(24!)}{4!(24)!}$

$C(28,4)=\frac{(28)(27)(26)(25)}{(4)(3)(2)(1)}$

$C(28,4)=20,475\ ways$

6 0

3 years ago

What is the equation of the line passing through the point (4, 5) that is parallel to the line with the equation

Reptile [31]

Answer:

y=2x-3

Step-by-step explanation:

1. find the slope

6x-3y=21

-3y=-6x+21 divide both sides by -3

y=2x-7

slope is 2

2.y-5=2(x-4)

y-5=2x-8

y=2x-8+5

y=2x-3

PARALLEL lines have the same slope

7 0

2 years ago

Give me a correct answer, My answer probably wrong.

Georgia [21]

Hello!

This is a problem about the general solution of a differential equation.

What we can first do here is separate the variables so that we have the same variable for each side (ex. $dy$ with the $y$ term and $dx$ with the $x$ term).

$\frac{dy}{dx}=\frac{x-1}{3y^2}$

$3y^2dy=x-1dx$

Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.

$y^3=\frac{1}{2}x^2-x+C$

Then here, we just solve for $y$ and we have our general solution.

$y=\sqrt[3]{\frac{1}{2}x^2-x+C}$

We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.

Hope this helps!

3 0

2 years ago