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2 years ago

Can someone help me solve this? Pls and ty!

Mathematics

2 answers:

Molodets [167]2 years ago

6 0

The person above is correct, give brainliest

Zanzabum2 years ago

5 0

Answer:

H. 95°

Step-by-step explanation:

m∠BGC is 10° smaller than m∠CGD, which means that m∠BGC is x° - 10°

m∠DGE is 25° more than m∠EGF, which means that m∠DGE is x° + 25°

The sum of all angles in a placement like this will always equal 360°

So we put all the measures of all angles on one side of thee equation and set it equal to 360*

x° + x° - 10° + 2x° + 25° + 2x° + 3x° + 30° = 360°

After combining like terms we get 9x° + 45° = 360°

After some algebra we get x = 35°

Now at the start we said that m∠DGE is x + 25°

Plug in 35° for x and we get 35° + 25°

The final answer is m∠DGE = 95°

Edit: Sorry if my answer looks a bit confusing. This is actually my first answer on Brainly so I'm quite new to this experience.

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A customer wants to tile their sunroom using 12" x24" tile which comes 9 pieces to a box the room is 8' by 9'6" calculate how ma

AysviL [449]

The number of pieces The customer will need actually is 38 tiles

The number of tiles in boxes the customer will buy is 45 tiles

Step-by-step explanation:

To solve the problem we will do these steps

1. Change the dimensions of the room from feet to inches

2. Calculate the area of the room

3. Calculate the area of one tile

4. Divide the area of the room by the area of the tile to find the number

of tills

5. Divide the number of tiles by the number of pieces in one box

to find the number of boxes he will need to buy

∵ The dimensions of the room are 8 feet by 9 feet 6 inches

∵ 1 foot = 12 inches

∴ 8 feet = 8 × 12 = 96 inches

∴ 9 feet 6 inches = 9 × 12 + 6 = 108 + 6 = 114 inches

∴ The dimensions of the sun room are 96" by 114"

The area of a rectangle is length × width

∵ Area of the room = 96 × 114 = 10944 inches²

∵ The dimensions of a tile are 12" by 24"

∴ Area of a tile = 12 × 24 = 288 inches²

∵ The number of tiles = Area room ÷ area tile

∴ The number of tiles = 10944 ÷ 288 = 38 tiles

The number of pieces The customer will need is 38 tiles

V.I.N:

The tiles come in boxes each box contains 9 pieces

∵ 38 ÷ 9 = 4.22

∴ He will need to buy 5 boxes with 45 tiles

The number of tiles in boxes is 45 tiles

Learn more:

You can learn more about the area of some figures in brainly.com/question/4459688

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4 0

3 years ago

Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m

Elenna [48]

Answer:

Part a: The probability of no arrivals in a one-minute period is 0.000045.

Part b: The probability of three or fewer passengers arrive in a one-minute period is 0.0103.

Part c: The probability of no arrivals in a 15-second is 0.0821.

Part d: The probability of at least one arrival in a 15-second period is 0.9179.

Step-by-step explanation:

Airline passengers are arriving at an airport independently. The mean arrival rate is 10 passengers per minute. Consider the random variable X to represent the number of passengers arriving per minute. The random variable X follows a Poisson distribution. That is,

$X \sim {\rm{Poisson}}\left( {\lambda = 10} \right)$

The probability mass function of X can be written as,

$P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots$

Substitute the value of λ=10 in the formula as,

$P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{{\left( {10} \right)}^x}}}{{x!}}$

Part a:

The probability that there are no arrivals in one minute is calculated by substituting x = 0 in the formula as,

$\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}}\\\\ = {e^{ - 10}}\\\\ = 0.000045\\\end{array}$

The probability of no arrivals in a one-minute period is 0.000045.

Part b:

The probability mass function of X can be written as,

$P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots$

The probability of the arrival of three or fewer passengers in one minute is calculated by substituting \lambda = 10λ=10 and x = 0,1,2,3x=0,1,2,3 in the formula as,

$\begin{array}{c}\\P\left( {X \le 3} \right) = \sum\limits_{x = 0}^3 {\frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}}} \\\\ = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^1}}}{{1!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^2}}}{{2!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^3}}}{{3!}}\\\\ = 0.000045 + 0.00045 + 0.00227 + 0.00756\\\\ = 0.0103\\\end{array}$

The probability of three or fewer passengers arrive in a one-minute period is 0.0103.

Part c:

Consider the random variable Y to denote the passengers arriving in 15 seconds. This means that the random variable Y can be defined as $\frac{X}{4}$

$\begin{array}{c}\\E\left( Y \right) = E\left( {\frac{X}{4}} \right)\\\\ = \frac{1}{4} \times 10\\\\ = 2.5\\\end{array}$

That is,

$Y\sim {\rm{Poisson}}\left( {\lambda = 2.5} \right)$

So, the probability mass function of Y is,

$P\left( {Y = y} \right) = \frac{{{e^{ - \lambda }}{\lambda ^y}}}{{y!}};x = 0,1,2, \ldots$

The probability that there are no arrivals in the 15-second period can be calculated by substituting the value of (λ=2.5) and y as 0 as:

$\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = {e^{ - 2.5}}\\\\ = 0.0821\\\end{array}$

The probability of no arrivals in a 15-second is 0.0821.

Part d:

The probability that there is at least one arrival in a 15-second period is calculated as,

$\begin{array}{c}\\P\left( {X \ge 1} \right) = 1 - P\left( {X < 1} \right)\\\\ = 1 - P\left( {X = 0} \right)\\\\ = 1 - \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = 1 - {e^{ - 2.5}}\\\end{array}$