Ammonium Chloride + Silver Nitrate ---<br> ------>

Chemical bonds are the electrical forces of attraction that hold atoms or ions together to form molecules. Different types of chemical bonds and their varying intensity are directly responsible for some of the physical properties of minerals such as hardness, melting and boiling points, solubility, and conductivity.

Explanation:

4 0

3 years ago

How can you distinguish between a physical change and a chemical change?

AleksAgata [21]

Answer:

Physical Change

When a substance undergoes a physical change, its composition remains the same despite its molecules being rearranged.
Physical change is a temporary change.
A Physical change affects only physical properties i.e. shape, size, etc.
A physical change involves very little to no absorption of energy.
Some examples of physical change are freezing of water, melting of wax, boiling of water, etc. .
In a physical change, no new substance is formed.
Physical change is easily reversible i.e original substance can be recovered.

Chemical Change

When a substance undergoes a chemical change, its molecular composition is changed entirely. Thus, chemical changes involve the formation of new substances.
.A chemical change is a permanent change.
Chemical change both physical and chemical properties of the substance including its composition
During a chemical reaction, absorption and evolution of energy take place.
A few examples of chemical change are digestion of food, burning of coal, rusting, etc.
A chemical change is always accompanied by one or more new substance(s).
Chemical changes are irreversible i.e. original substance cannot be recovered.

8 0

3 years ago

A student places a 100.0°C piece of metal that weighs 85.5 g into 122 mL of 16.0°C water. If the final temperature is 20.2°C, wh

Musya8 [376]

Answer:

The specific heat of the metal is 0.314 J/g°C

Explanation:

Step 1: data given

Temperature of the piece of metal = 100.0 °C

Mass of the metal = 85.5 grams

Volume of water = 122 mL = 122 grams

Temperature of water = 16.0 °C

The final temperature of water = 20.2 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of metal

Heat gained= heat lost

Qgained = - Qlost

Qwater = -Qmetal

Q = m*c* ΔT

m(metal)*c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

⇒m(metal) = mass of metal = 85.5 grams

⇒c(metal) = the specific heat of metal = TO BE DETERMINED

⇒ΔT(metal) = the change of temperature of metal = T2 - T1 = 20.2 - 100 °C = -79.8 °C

⇒m(water) = the mass of water = 122 grams

⇒c(water) = the specific heat of water = 4.184 J/g°C

⇒ΔT(water) = the change of temperature of metal = T2 - T1 = 20.2 - 16.0 °C = 4.2 °C

85.5 *c(metal) * -79.8 = -122 * 4.184 * 4.2

c(metal) * (-6822.9) = -2143.9

c(metal) = 0.314 J/g°C

The specific heat of the metal is 0.314 J/g°C

7 0

3 years ago

Ammonium Chloride + Silver Nitrate --- ------>