Given :
Molarity of sulfuric acid solution is 3.0 M.
Amount of sulfuric acid present in solution is 9.809 g.
To Find :
The volume of solution.
Solution :
We know, molarity is given by :

Therefore, volume required is 33.33 ml .
Answer:
0.3 mole
Explanation:
number of moles grams
one 14+(4×1)+14+(3×16)
1 80
? 24
Therefore, 24×1÷80 = 0.3 moles of ammonium nitrate