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2 years ago

How can bonding determine the properties of a substance?

Chemistry

1 answer:

levacccp [35]2 years ago

4 0

Answer:

Chemical bonds are the electrical forces of attraction that hold atoms or ions together to form molecules. Different types of chemical bonds and their varying intensity are directly responsible for some of the physical properties of minerals such as hardness, melting and boiling points, solubility, and conductivity.

Explanation:

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Mars2501 [29]

Explanation:

area of rectangle=l×b

15=5×b
b=3cm

2.area of rectangle=l×b

28=l×4
l=7cm

3. perimeter of square=4×L

24=4×L
L=6cm

4. perimeter of rectangle=2(L+b)

14=2(4+b)
14=8+2b
2b=6
b=3cm

hope it helps.

4 0

2 years ago

Read 2 more answers

What is a nonpolar covalent bond?

Vlad1618 [11]

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

A non-polar covalent bond is defined as the bond which is formed between the atoms having no difference in electronegativity values. For Example: $Cl_2,H_2$ etc..

In this bond, the electrons are shared equally and $\Delta EN$ value is equal to 0.

Hence, the correct answer is Option D.

8 0

2 years ago

During a lab, a student holds a magnesium ribbon in a flame. Which of the following is the magnesium ribbon considered?

Aleks [24]

It will be B trust me

5 0

2 years ago

Predict the sign of the entropy change,Delta S, for each of the following reactions:The signs are either going to be pos or nega

algol [13]

Answer: a) $Pb^{2+}(aq)+2Cl^-(aq)\rightarrow PbCl_2(s)$ : negative

b) $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$ : positive

c) $2NH_3(g)\rightarrow N_2(g)+3H_2(g)$ : positive.

d) $P_4(g)+5O_2(g)\rightarrow P_4O_{10}(s)$ : negative

e) $C_4H_8(g)+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)$ : positive.

f) $I_2(s)\rightarrow I_2(g)$ : positive.

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

$\Delta S$ is positive when randomness increases and $\Delta S$ is negative when randomness decreases.

a) $Pb^{2+}(aq)+2Cl^-(aq)\rightarrow PbCl_2(s)$

As ions are moving to solid form , randomness decreases and thus sign of $\Delta S$ is negative.

b) $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

As solid is changing to gas, randomness increases and thus sign of $\Delta S$ is positive.

c) $2NH_3(g)\rightarrow N_2(g)+3H_2(g)$

As 2 moles of reactants are converted to 4 moles of products , randomness increases and thus sign of $\Delta S$ is positive.

d) $P_4(g)+5O_2(g)\rightarrow P_4O_{10}(s)$

As gas is changing to solid, randomness decreases and thus sign of $\Delta S$ is negative.

e) $C_4H_8(g)+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)$

As 7 moles of reactants are converted to 8 moles of products , randomness increases and thus sign of $\Delta S$ is positive.

f) $I_2(s)\rightarrow I_2(g)$

As solid is changing to gas, randomness increases and thus sign of $\Delta S$ is positive.

6 0

2 years ago

In Universe , recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quant

tiny-mole [99]

Answer:

Check the explanation

Explanation:

When talking about our universe there are 5 d orbitals. The element of first transition series moves away from the universal principles of Hund's rule and Aufbav's principle. So in order to attain stability these elements tend to form half or full filled orbitals.

In our universe the ground state electronic configuration of sixth transition metal, Iron (Fe) : [Ar] $3d^{6} 4s^{2}$

and the electronic configuration of seventh transition metal, Cobalt (Co) : [Ar] $3d^{7} 4s^{2}$

=================================

In universe L there are seven orbitals.

Ground state electronic configuration of sixth and seven transition element.

Sixth transition metal: [Ar] $3d^{7} 4s^1 or [X] 3d^{7} 4s^1$

Seventh transition metal: [Ar] $3d^{7} 4s^{2}or [X] 3d^{7} 4s^{2}$

7 0

2 years ago