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nadya68 [22]
2 years ago
6

Determine which postulate or theorem can be used to prove that ABD=CBD.

Mathematics
1 answer:
AlladinOne [14]2 years ago
4 0
The answer is A SSS because
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a washer and a dryer cost 659$ combined. The washer costs 91$ less than the dryer, how much was the dryer?  
Darina [25.2K]
W+D=659

W=D-91

---------------------------

(D-91)+D=659

D-91+D=659

2D=750

D=750/2=375

------------------------------

W+375=659

W=284

------------------------------

So the dryer had cost $375 and the washer had cost $284.
7 0
3 years ago
Read 2 more answers
32) (a)-(c) pre calculus
Harrizon [31]
Well, remember we can't take the square root of a negative

so we see that we have \sqrt{1-x^2}
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]

a. D=[-1,1] or from -1 to 1 is domain


b. for a TI-84, go to y-editor then input 4x \sqrt{1-x^2} for y1

c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7



A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7


8 0
3 years ago
Does anyone know how to solve this <br> The answer is B but can anyone explain why
Lana71 [14]

Answer:

B. (0,-1)

Step-by-step explanation:

see.. i'm not rude.... :/

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216%5C%5C%7D" id="TexFormula1" title="\sqrt[3]{216\\}" alt="\sqrt[3]{216\\}"
aivan3 [116]

Answer:

6

Step-by-step explanation:

\sqrt[3]{216} = \sqrt[3]{8} · \sqrt[3]{27}  =  \sqrt[3]{2}³ · \sqrt[3]{3}³ = 2 x 3  = 6

7 0
2 years ago
What is the greatest common factor of 12 and 16
Assoli18 [71]

Answer:

4

Step-by-step explanation:

12 can be dived into 4 a total of 3 times. 16 can be divided into 4 a total of 4 times

5 0
3 years ago
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