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ch4aika [34]
2 years ago
13

Determine an equation that describes the function based on the particle set of values in the table below

Mathematics
1 answer:
likoan [24]2 years ago
3 0

Answer: B

Step-by-step explanation:

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Graph the line with slope 1/2 passing through the point (5, - 1)
True [87]

Answer:

<u><em>The equation is y = (1/2)x + - 3.5</em></u>

Step-by-step explanation:

We look for an equation with the form y = mx + b, where m is the slope and b the y-intercept.

We're given the slope, (1/2) which we can use for m:

y = (1/2)x + b

We are told the line goes through (5,-1).  We need a value of b that will move the line to include this point.  Do that by substituting the values:

 x = 5, and y= -1

y = (1/2)x + b

-1 = (1/2)*5 + b

-1 = (2.5) + b

- 3.5 =   b

<u><em>The equation is y = (1/2)x + - 3.5</em></u>

See the attached image.

7 0
1 year ago
Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized
Roman55 [17]

Answer:

Option B.

Step-by-step explanation:

The given triangle is a right angle triangle.

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

In the given triangle,

\tan (45^{\circ})=\dfrac{v}{7}

1=\dfrac{v}{7}

7=v

Using Pythagoras theorem, we get

hypotenuse^2=Perpendicular^2+Base^2

u^2=v^2+7^2

u^2=7^2+7^2

u^2=2(7^2)

Taking square root on both sides, we get

u=\sqrt{2(7^2)}

u=7\sqrt{2}

Therefore, the correct option is B.

6 0
3 years ago
Compute show all of your work: 8X4-4/2+1
Pepsi [2]
8*4-4/2+1    
32-4/2+1
32-2+1
=31 answer 
So, the answer to this question is 31

5 0
3 years ago
Can any one help me if you do you will recive 30 points please help :,(
kodGreya [7K]
1. so since we assume that CF is a straight line that means that the angle CAF is 180 angle CAD is 90 and FAE is 65 so 180-(65+90)=DAE=25

2. so since angle QPR= angle TPS (both are signified by f) and we assume that QT is straight so then QPT=180
180-154=2f=26
angle f=13
QPR=13

3. so we assume that BG is straight so it is 180
we add up the known angles (BQD+DQE+FQG=10+103+12=125) 180-125=DQC+EQF=55=2x+3x=5x
5x=55
x=11
CQD=2x=22
EQF=3x=33

4. we know that x=x and the whole is 360 so
x+x+x+x+71+71+71+71=360=4x+284=360
4x=76
x=19

8. so we assume that EF and CD are straight lines so EQD=CQF so 155=56+3x so
99=3x
CQG=99

9. so adjacent and the ratio is 4:5 so a line is 180 so 4+5=9 180/9=20  20*4=80 20*5=100 4:5 =80:100

a. 80 and 100
b. you should be able to do this

10. so on a line is 180
a. 3:4:5  3+4+5=12  180/12=15
3*15=45  4*15=60  5*15=75
3:4:5 =45:60:75
the angles are 45 60 75

b. you should be able to do this from my work

5 0
3 years ago
Look at the following sequence. 51, 5.1, 0.51, 0.051, . . .
lukranit [14]
Hello there.
The sequence is being divided by ten
51/10= 5.1
5.1/10 = 0.51
0.51/10 = 0.051,
and so on.
You can also reverse the following sequence and multiply it by ten.
3 0
3 years ago
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