Question

Solve the equation in the complex number system.

Answer 1

Answer:

Step-by-step explanation:

$25x^2-10x+2=0\\x=\frac{10 \pm\sqrt{(-10)^2-4\times 25\times 2} }{2 \times 25 } \\x=\frac{10 \pm \sqrt{100-200}}{2 \times 25} \\x=\frac{10 \pm \sqrt {100 \iota^2}}{50} \\x=\frac{10 \pm ~10~\iota}{50} \\x=0.2 \pm 0.2 \iota\\x=0.2+0.2 \iota\\or ~x=0.2-0.2 \iota$