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kotykmax [81]
2 years ago
9

Is x=16 the solution to the equation x−12=4?

Mathematics
2 answers:
Anna [14]2 years ago
7 0

Answer: Yes it would be x=16

slavikrds [6]2 years ago
3 0

Answer:

Yes. 16 - 12 = 4.

Step-by-step explanation:

If the value of x = 16, then just plug it in

x - 12 = 4

  ∫

16 - 12 = 4

Check our answer:

4 + 12

4 + 10 = 14

14 + 2 = 16

16 - 12 = 4

(Answer is 16 - 12 = 4.)

This is the correct solution.

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Walden’s family is shopping for a reclining chair. The chair the family decided on has a retail price of $800 plus 5% sales tax
Marianna [84]

Answer:

B 10% off sale, with a total price to pay of 756

Step-by-step explanation:

Retail price (Rp) = $800

Taxes (T) = 5%

  • Offer A $75 instant rebate

Total price A (TA) = Rp - 75 + (Rp - 75) 5%

TA = 800 - 75 + (800-75) 5%

TA = 725 + 725 5%

725 5% = 725*5/100 = 36.25

TA= 725+36.25 = $761.25

  • Offer B 10% off sale

Total price B (TB) = RP - RP 10% + (RP - RP 10%) 5%

TB = 800 - 800 10% + (800 - 800 10%) 5%

800 10% = 800*10/100 = 80

TB = 800 - 80 + (800 - 80) 5%

TB = 720 + 720 5%

720 5% = 720*5/100 = 36

TB = 720 + 36 = $756

  • Offer C 5% off sale plus store pays sales tax

store pays sales tax means Walden's family will not need pay for taxes

Total price C (TC) = RP - RP 5%

TC = 800 - 800 5%

800 5% = 800*5/100 = 40

TC = 800 - 40 = $760

  • Offer D a “no tax” sale—the store pays the tax

Means that Walden's family will need pay just the retail price

TD = $800

The beast deal is from the store B

7 0
3 years ago
Read 2 more answers
on the first play the football team loss 6 yards. on the second play the team lost 5 yards. what was their total?
Neporo4naja [7]
-11 or the Team lost 11 yards
8 0
3 years ago
Read 2 more answers
Reducing fractions 5 to 30
Bumek [7]

Answer: 1 to 6 or 1/6

Step-by-step explanation:

5 to 30 is 5/30

simplify to 1/6 because both the 5 and 30 are divisible by 5

4 0
2 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
2 years ago
Help me ASAP for this question
ivann1987 [24]

Answer: Y= 2x

Step-by-step explanation:

1 x 2 = 2

3.4 x 2 = 6.8

5 x 2 = 10

7 x 2 = 14

So. Y = 2x

4 0
3 years ago
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