The two gears are shown n the diagram below.
ω₁ and ω₂ are the angular velocities of the larger and smaller gears respectively.
Part 1.
When the smaller gear makes one revolution, it turns through an angle of 2π radians or 360°.
Because the gears do not slip, the larger gear turns through an angle of θ, so that
(θ radians)*(8 in) = (2π radians)*(2 in)
or
8θ = 4π
θ = π/2 radians = 90°
Answer: 90.0°
Part 2.
When the larger gear makes one revolution, it turns through an angle of 2π radians.
Because the gears do not slip, the smaller gear turns through an angle φ, such that
(2 in)*(φ radians) = (8 in)*(2π radians)
or
2φ = 16π
φ = 8π radians
= (8π radians)*(1/2π rotations/radian)
= 4 rotations
Answer: 4 rotations
Answer:
(x+y)/xy or (1/x + 1/y) portion of the leaves
Step-by-step explanation:
Let the total work done to rake the leaves be a for representation.
Thus,
given Maya takes x minutes to rake the leaves
thus,
work done by may in x minutes = a
dividing both side by x
work done by maya in x/x = 1 minutes = a/x
similarly
given Calra takes y minutes to rake the leaves
thus,
work done by may in y minutes = a
dividing both side by y
work done by maya in y/y = 1 minutes = a/y
__________________________________
Total work done by both in 1 minutes = a/x + a/y = a(1/x+1/y) = a(x+y)/xy
Thus, if a is the total work , then they do (x+y)/xy of a work in one minute.
Thus, (x+y)/xy portion of leaves do they rake in one minute if they work together.
Sorry but we need the numbers
Answer:
a = 20; b = 2√101
Step-by-step explanation:
The triangle at upper left and the one at lower right are similar. Ratios of corresponding sides are equal, so ...
200/a = a/2
400 = a^2
√400 = 20 = a
Then, by the Pythagorean theorem, the value of b can be found:
b = √(a^2 + 2^2) = √(400 +4) = √4·√101
b = 2√101