The given histogram represents <span>the number of hamburgers students ate in a month :
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From the histogram we can conclude the following:
(1) 8 students ate (0 - 4) hamburgers
(2) 3 students ate (5 - 9) <span>hamburgers </span>
(3) 2 students ate (10 - 14) <span>hamburgers
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note: we don't know how many students ate exactly 5 hamburgers.
<span>So, the answer
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The information which is provided in the histogram<span>
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</span><span>The number of students who ate 10 hamburgers or more
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In order to solve this we'll start by assigning variables to hamburgers and cheeseburgers, since these are what we're trying to find. Lets say x = hamburgers and y = cheeseburgers. So we know two things, we know that x+y= 763 (hamburgers plus cheeseburgers sold equals 763, and we know that y= x+63 (cheeseburgers sold equals 63 more than hamburgers sold). Now we have a system of equations. This can be solved most easily by rearranging each equation to each y, and then set them equal to each other:
x+y=763 -> y=763-x, and we already have y=x+63. Set them equal to each other:
x+63 = 763-x (add x to both sides) -> 2x+63 = 763 (subtract 63 from both sides) -> 2x = 700 (divide both sides by 2) x = 350. So we solved for x, which is hamburgers sold, which is what the question asks for, so your answer is 350 hamburgers were sold on Saturday
The answer is A becaues 119 thousand times 10 equals 1190000
then you divide it by 100 to get A.119 hunderths
Start by y-k=m(x-h)
m= 3
k=2
h=1
so y-2=3(x-1)
distribute
y=3x-3+2
final answer: y=3x-1
B shows her getting closer to home, immediately turning round, gives time for finding book then riding all the way home at a constant speed
