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2 years ago

5

I WILL MARK FIRST ANSWER BRAINLIEST !!! PLS ANSWER QUICKLY !!!

2 answers:

Zarrin [17]2 years ago

7 0

Answer:

104x + 52

None of the expressions listed are equivalent to 52(2x + 1)

Step-by-step explanation:

52(2x + 1)

Apply the distributive law: a(b + c) = ab + ac

⇒ 104x + 52

Therefore, 52(2x + 1) = 104x + 52

Anon25 [30]2 years ago

7 0

$\rm 52(2x + 1)$

Use distributive property: a(b+c)=ab+bc

a = 52

b = 2x

c = 1

$\rm \: 52 \times 2x + 2x \times 1$

Multiply the numbers

$\rm \: 104x + 2x$

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B) y = log2 (4" - 4)<br> find the inverse of this equation

GuDViN [60]

Answer:

$y = \frac{1}{4} \times {2}^{x} - 1$

Step-by-step explanation:

Assuming the given logarithmic equation is

$y = \log_{2}( {4}{x } - 4)$

We interchange x and y to get:

$x= \log_{2}( {4}{y} - 4)$

We solve for y now:

${2}^{x} = {4}{y} - 4$

We add 4 to both sides to get;

${2}^{x} + 4 = 4y$

Divide through by 4:

$y = \frac{1}{4} \times {2}^{x} - 1$

4 0

3 years ago

Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o

Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, $\mu$ = 5.5 mins

Standard deviation, $\sigma$ = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ $z_1=\frac{x_1-\mu}{\sigma}$ ...raw score, $x_1$ = $5.4$

⇒ Plugging the values.

⇒ $z_1=\frac{5.4-5.5}{0.4}$

⇒ $z_1=-0.25$

For raw score 5.5 the z score is.

⇒ $z_2=\frac{5.8-5.5}{0.4}$

⇒ $z_2=0.75$

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ $P(5.4$

⇒ $P(-0.25$

⇒ $P(z$

⇒ $z(1.5)=0.7734$ and $z(-0.25)=0.4013$ .<em>..from z -score table.</em>

⇒ $0.7734-0.4013$

⇒ $0.3721$

To find the percentage we have to multiply with 100.

⇒ $0.3721\times 100$

⇒ $37.21$ %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

4 0

2 years ago

How do you solve number 13 and 14?

Ulleksa [173]

This is what I got hope u get it right gl

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2 years ago

4х+6y = 40<br> 2х+бу= 26<br><br> How do u do the work for this equation

Dovator [93]

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7 0

3 years ago

vlabodo [156]

Answer:

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Step-by-step explanation:

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2 years ago