Answer:
(C) 2√15
Step-by-step explanation:
Recognize that all the triangles are right triangles, so are similar to each other. In these similar triangles, the ratio of the short side to the long side is the same for all.
... CB/CA = CT/CB
... CB² = CA·CT = 10·6 = 60 . . . . . . . . . . multiply by CA·CB; substitute values
... CB = √60 = 2√15 . . . . . . . take the square root; simplify
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<em>Comment on this solution</em>
The altitude to the hypotenuse of a right triangle (CB in this case) divides the hypotenuse into lengths such that the altitude is their geometric mean. That is ...
... CB = √(AC·CT) . . . . as above
This is true for any right triangle — another fact of geometry to put in your list of geometry facts.
<h2>
Hello!</h2>
The answers are:
The possible values for x in the equation, are:
First option, ![5\sqrt[3]{3}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B3%7D)
Second option, ![\sqrt[3]{375}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B375%7D)
<h2>
Why?</h2>
To solve the problem, we need to remember the following properties of the exponents and roots:
![a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}](https://tex.z-dn.net/?f=a%5Csqrt%5Bn%5D%7Bb%7D%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bn%7D%2Ab%7D%20%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%5C%5C%5C%5C%28a%5E%7Bb%7D%29%5E%7Bc%7D%3Da%5E%7Bb%2Ac%7D)
Then, we are given the expression:
So, finding "x", we have:
![x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}](https://tex.z-dn.net/?f=x%5E%7B3%7D%3D375%5C%5C%5C%5C%28x%5E%7B3%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%28375%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B375%7D%3D%5Csqrt%5B3%5D%7B125%2A3%7D%3D%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B3%7D%3D5%5Csqrt%5B3%5D%7B3%7D)
Hence, the possible values for x in the equation, are:
First option,
Second option,
Have a nice day!
9514 1404 393
Answer:
a non-negative integer
Step-by-step explanation:
Powers of variables in a polynomial are whole numbers, that is, non-negative integers.
For f(x) to be a polynomial function, the value of n must be a whole number.
Answer:
3
Step-by-step explanation:
lim(t→∞) [t ln(1 + 3/t) ]
If we evaluate the limit, we get:
∞ ln(1 + 3/∞)
∞ ln(1 + 0)
∞ 0
This is undetermined. To apply L'Hopital's rule, we need to rewrite this so the limit evaluates to ∞/∞ or 0/0.
lim(t→∞) [t ln(1 + 3/t) ]
lim(t→∞) [ln(1 + 3/t) / (1/t)]
This evaluates to 0/0. We can simplify a little with u substitution:
lim(u→0) [ln(1 + 3u) / u]
Applying L'Hopital's rule:
lim(u→0) [1/(1 + 3u) × 3 / 1]
lim(u→0) [3 / (1 + 3u)]
3 / (1 + 0)
3
