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e-lub [12.9K]
3 years ago
14

Una bolsa contiene 3 canicas rojas, 8 azules y 10 amarillas. ¿Cuál es la razón de canicas rojas al total de canicas en su forma

más simple? ​
Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

porque hay un total de 21 canicas y 3 de ellas son rojas, en forma mas simple de cada 7 canicas una es roja o 1:7 es el razon de canicas rojas a todas

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Suppose a Pony Express rider was paid $192 for 12 weeks of work. If he was paid the same amount each week,how much was he paid f
Masteriza [31]
$192 divided by 12 is 16 so 16 x 3 is 48. That is your answer $48. Your welcome bud.
5 0
3 years ago
PQ=2x+1 and QR=5x-44; Find PR
Dima020 [189]

Answer:

x=15

Step-by-step explanation:

subtract 1 from both sides so you are left with 2x=5x-45

then subtract 5x from both sides and you have -3x=-45

then finally divide -3 from -45 to get x=15

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Which of the following describes the graph below
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b

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3 years ago
3. Suppose the mystery bag had resulted in the following number of red chips. Using the simulated sampling distributions found e
Vinvika [58]

Answer:

a) 0.172

b) 0.167

c) 0.1404

Step-by-step explanation:

Margin of error, E = 2\times\sqrt{\frac{p(1-p)}{n}}

here,

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n = sample size

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p = 10 ÷ 30 = 0.333

Therefore,

E = 2\times\sqrt{\frac{0.333(1-0.333)}{30}}

= 2 × 0.0861

= 0.172

b)  n = 30

p = 21 ÷ 30 = 0.7

Therefore,

E = 2\times\sqrt{\frac{0.7(1-0.7)}{30}}

= 2 × 0.0836

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3 0
3 years ago
Part 1
Dmitrij [34]

Answer:

a)  A n  (B' n C') =  {3, 9}.

b) (AUB) n (BUC) = {2,4,5,6,7,8}

Step-by-step explanation:

a)  Rewriting C ; C = {4,5,6,7,8}

B' = {3,5,7,9} and C' = {2, 3, 9}

so (B' n C') = {3, 9}

and A n  (B' n C') =  {3, 9}.

b)  {A U B} = { 2,3,4,5,6,7,8,9} and {B U C} = {2,4,5,6,7,8}

so (AUB) n (BUC) = {2,4,5,6,7,8}

4 0
3 years ago
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