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bonufazy [111]
3 years ago
14

Connecting many devices in a single socket does not affect the flow of current in a

Physics
2 answers:
MakcuM [25]3 years ago
7 0
The answer most likely false!
Bess [88]3 years ago
3 0
It is Going to be False
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Kevin is a major stockholder in Professional Transmission Services (PTS), a nationwide network of transmission repair shops foun
const2013 [10]

Answer:

Kevin wants to make the firm private

Explanation:

Based on the information provided within the question in regards to the situation it seems that Kevin wants to make the firm private. Private Firms are companies that are owned by non-governmental entities or instead owned by  a single individual or a very small amount of shareholders. Which is what Kevin seems to be wanting to do since he wants to buy back all the shares of the company so that only his family owns the company.

If you have any more questions feel free to ask away at Brainly.

6 0
3 years ago
1. Current is usually the flow of
kolbaska11 [484]

Answer:

1. Current is usually the flow of <u>electrons</u>.

Explanation:

The flow of charges through a wire or conductor is called electric current.

7 0
3 years ago
Read 2 more answers
Which of the following indicates a heat transfer?
lesya [120]

Answer:

TEMPERATURE CHANGES

Explanation:

WELL ITS BASIC. WHEN TEMPERATURE CHANGES. IT MEANS THAT HEAT IS BEING TRANSFERRED AS I HEARD THAT COLD CANNOT BE TRANSFERRED

3 0
3 years ago
A silver wire with resistivity 1.59 × 10-8 Ω-m carries a current density of 4.0 A/mm2, What is the magnitude of the electric fie
Nat2105 [25]

Answer:

Electric field, E = 0.064 V/m

Explanation:

It is given that,

Resistivity of silver wire, \rho=1.59\times 10^{-8}\ \Omega-m

Current density of the wire, J=4\ A/mm^2=4\times 10^6\ A/m^2

We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :

E=J\times \rho

E=4\times 10^6\times 1.59\times 10^{-8}

E = 0.0636 V/m

or

E = 0.064 V/m

So, the magnitude of electric field inside the wire is 0.064 V/m. Hence, this is the required solution.

6 0
3 years ago
A thin, uniform rod is hinged at its midpoint. to begin with, one-half of the rod is bent upward and is perpendicular to the oth
bazaltina [42]
<span>Answer: initial I = (m/2)L²/3 + (m/2)L² where L = ½ the length of the rod, and the vertical half can be treated as a point mass. initial I = mL²(1/6 + 1/2) = 2mL²/3 final I = m(2L)²/3 = 4mL²/3 Since I has doubled and momentum is conserved, ω has halved. ω = 3.9 rad/s. Formulaically: 2mL²/3 * 7.8rad/s = 4mL²/3 * ω</span>
5 0
4 years ago
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