Answer: It stays the same, it is constant no matter what.
Explanation: Just because it may go faster/slower due to altitude change, it does not affect the weight.
Answer:
southwest
Explanation:
Here, all the particles have same charge this means that only repulsive force is acting on the particles according to Coulomb's laws.
One particle is 1 m to my north and another particle is to my east.
The particle to my north will push the positive charge I am holding to the south and the particle to my east will push the positive charge I am holding to the west.
Hence, the resultant direction of the force will be southwest.
<u>Answer:</u> The amount of energy released in the process is 4.042 MeV.
<u>Explanation:</u>
The chemical reaction for the fusion of deuterium nucleus follows the equation:

Atomic mass of the nucleus also contains some mass of the electrons.
Mass of electron in
is 
- <u>Calculating the mass of deuterium nucleus:</u>

So, initial mass of the reaction = ![2[(1876.124MeV/c^2)-(0.511MeV/c^2)]=3751.226MeV/c^2](https://tex.z-dn.net/?f=2%5B%281876.124MeV%2Fc%5E2%29-%280.511MeV%2Fc%5E2%29%5D%3D3751.226MeV%2Fc%5E2)
- <u>Calculating the mass of tritium nucleus:</u>


So, final mass of the reaction = ![2803.921-[(1.007267u\times 931.494MeV/c^2.u)]=3747.184](https://tex.z-dn.net/?f=2803.921-%5B%281.007267u%5Ctimes%20931.494MeV%2Fc%5E2.u%29%5D%3D3747.184)
Difference between the masses of the nucleus:

Energy released in the process is calculated by using Einstein's equation, which is:

Putting value of
in above equation, we get:

Hence, the amount of energy released in the process is 4.042 MeV.
The answer should be A weighlifter lifting 100lb. bell bar from his chest to a certain height.
Answer:
Very easy question
For x-component, we use Fₓ = Fcosα
For y-component, we use Fy = Fsinα
The major problem is with angle α.
Here α = 90+30
Because the angle is measured from +ve X-axis.
By putting values if you know co-ratios that how Sin and cos Convert to each other then you have got it.
So for further calculation,
Fₓ = Fcos(90+30) = 25(-sin30)
Fₓ = -25(1/2) = 25/2 = 12.5 - will be eliminate because force in magnitude is not "-ve"
As it is
Fy = Fsin(90+30) = Fcos30
Fy = 25 (√3 /2) = 25√3/2
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