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2 years ago

PLS HELP What are the right answers? Or is this correct?

Mathematics

1 answer:

LekaFEV [45]2 years ago

7 0

Answer:

i think your correct my bro

Step-by-step explanation:

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What is the product of 379 and 8

levacccp [35]

Product means multiplication, so I would multiply 379 and 8.
379 x 8 = 3032
3032 is directly in between 3031 and 3033

6 0

3 years ago

Read 2 more answers

Ilia_Sergeevich [38]

Answer:

A. 5 to the power of negative 5 over 6

Step-by-step explanation:

$\sqrt[3]{5} \sqrt{5} /\sqrt[3]{5^5} =$
$5^{1/3+1/2-5/3}=$
$5^{1/2-4/3}=$
$5^{3/6-8/6}=$
$5^{-5/6}$

6 0

2 years ago

According to the Mortgage Bankers Association, 8% of U.S. mortgages were delinquent in 2011. A delinquent mortgage is one that h

shepuryov [24]

Answer:

The probability that exactly one of these mortgages is delinquent is 0.357.

Step-by-step explanation:

We are given that according to the Mortgage Bankers Association, 8% of U.S. mortgages were delinquent in 2011. A delinquent mortgage is one that has missed at least one payment but has not yet gone to foreclosure.

A random sample of eight mortgages was selected.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 mortgages

r = number of success = exactly one

p = probability of success which in our question is % of U.S.

mortgages those were delinquent in 2011, i.e; 8%

LET X = Number of U.S. mortgages those were delinquent in 2011

So, it means X ~ $Binom(n=8, p=0.08)$

Now, Probability that exactly one of these mortgages is delinquent is given by = P(X = 1)

P(X = 1) = $\binom{8}{1}\times 0.08^{1} \times (1-0.08)^{8-1}$

= $8 \times 0.08 \times 0.92^{7}$

= 0.357

Hence, the probability that exactly one of these mortgages is delinquent is 0.357.

4 0

3 years ago

-8(3 - 4v) + 8v = 9v + 3 what is the answer?

gavmur [86]

Answer:

My sister and her sister and my mom are so adorable I love her and

Step-by-step explanation: was the name wrong I was talking to him about it haha is that a little

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3 years ago

At 2:00pm a car's speedometer reads 20mph, and at 2:10pm it reads 30mph.

Dmitry [639]

Over this 10-minute interval, the car's average acceleration is

$\dfrac{30\,\mathrm{mph}-20\,\mathrm{mph}}{10\,\mathrm{min}}=\dfrac{10\,\mathrm{mph}}{\frac16\,\mathrm h}=60\dfrac{\rm mi}{\mathrm h^2}$

The MVT says that at some point during this 10-minute interval, the car must have had an acceleration of 60 mi/h^2.

6 0

3 years ago