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Anna007 [38]
3 years ago
9

Math problem I need help on

Mathematics
1 answer:
JulijaS [17]3 years ago
8 0

Answer:I think the answer is

1. x=8

Step-by-step explanation:

1. X=8

2. X=1⅓

3. 0x=-12

4. -8x=0

5. 0x=24

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Snap company issues 10% five year bonds on january 1 of this year, with a par value of 120,000 and semiannual interest payments
mezya [45]

Answer:

<h3>$189,292.92</h3>

Step-by-step explanation:

Using the compound interest formula to get the equivalent amount after 5 years;

A = P(1+r/n)^nt

P is the principal = 120,000

r is the rate = 10% = 0.1

t is the time = 5 years

n is the time of compounding = 1/2  = 0.5(semi annual interest)

Substitute into the formula;

A = 120,000(1+0.1/0.5)^(5)(0.5)

A = 120,000(1+0.2)^2.5

A = 120,000(1.2)^2.5

A = 120,000(1.5774)

A =  189,292.92

Hence the company issue is $189,292.92

4 0
3 years ago
Write the number 119,000,003 in two other forms
pantera1 [17]
One hundred million and three dollars
100,000,000+10,000,000,+9,000,000+3
6 0
3 years ago
Read 2 more answers
Simplify 4 whole 2/7 + 5/7
tia_tia [17]

Answer:

1

Step-by-step explanation:

2/7+5/7=7/7=1 because 7/7 would be a 1 whole

4 0
3 years ago
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HELP!!! WILL GIVE BRAINLIEST FOR CORRECT ANSWER!!!
Naddika [18.5K]

Answer:

can i just take the points?

Step-by-step explanation:

6 0
3 years ago
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A research company desires to know the mean consumption of milk per week among males over age 25. A sample of 650 males over age
Advocard [28]

Answer:

3.3\leq x\leq 3.5

Step-by-step explanation:

The 95% confidence interval can be calculated as:

x'-z_{\alpha/2}\frac{s}{\sqrt{n}} \leq x\leq x'+z_{\alpha/2}\frac{s}{\sqrt{n}}

Where x is the mean consumption of milk, x' is the sample mean, s is the population standard deviation, n is the size of the sample, \alpha is 5%  and z_{\alpha /2} is the z-value that let a probability of \alpha /2 on the right tail.

So, replacing x' by 3.4 liters, s by 1.3 liters, n by 650 and z_{\alpha /2} by 1.96, we get that the 95% confidence interval is equal to:

3.4-(1.96*\frac{1.3}{\sqrt{650}})\leq x\leq 3.4+(1.96*\frac{1.3}{\sqrt{650}}) \\3.4-0.1\leq x\leq 3.4+0.1\\3.3\leq x\leq 3.5

4 0
3 years ago
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