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3 years ago

The numbers in this chart represent the weights in kilograms of five

Mathematics

2 answers:

monitta3 years ago

8 0

Answer:

<em>John’s is the outlier in the data set</em>

Step-by-step explanation:

Nitella [24]3 years ago

3 0

John’s is the outlier

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Given that f(x) = 4x√3x + 3 and g(x) = 2√x+1, find (f/g)(x)

Tresset [83]

Answer:

$2x\sqrt{3}.$

Step-by-step explanation:

$\frac{f}{g}(x)=\frac{4x\sqrt{3x+3}}{2\sqrt{x+1}}=\frac{2*2*x*\sqrt{3}*\sqrt{x+1}}{2*\sqrt{x+1}}=2x\sqrt{3}.$

8 0

2 years ago

Y'all -<br> please help <br> I have been on this question for like 20 mins

AURORKA [14]

Answer:

Step-by-step explanation:

5 0

3 years ago

0.3(4-x)=x-1.4 how do you solve this problem?

tresset_1 [31]

Answer:

x = 2.

Step-by-step explanation:

Solve for x:

0.3 (4 - x) = x - 1.4

Expand out terms of the left hand side:

1.2 - 0.3 x = x - 1.4

Subtract x from both sides:

1.2 + (-0.3 x - x) = (x - x) - 1.4

-0.3 x - x = -1.3 x:

-1.3 x + 1.2 = (x - x) - 1.4

x - x = 0:

1.2 - 1.3 x = -1.4

Subtract 1.2` from both sides:

(1.2 - 1.2) - 1.3 x = -1.2 - 1.4

1.2 - 1.2 = 0:

-1.3 x = -1.2 - 1.4

-1.2 - 1.4 = -2.6:

-1.3 x = -2.6

Divide both sides of -1.3 x = -2.6 by -1.3:

(-1.3 x)/(-1.3) = (-2.6)/(-1.3)

(-1.3)/(-1.3) = 1:

x = (-2.6)/(-1.3)

(-2.6)/(-1.3) = 2.:

Answer: x = 2.

4 0

3 years ago

In this assignment, you will explore how the volume is changed when you adjust the height or radius of a cylinder. You will drag

lesantik [10]

The volume of a cylinder changes when you adjust the height or radius as the volume either increases or reduces.

<h3>How to illustrate the volume?</h3>

Let's assume that the height and radius are 14cm and 7cm. The volume will be:

= πr²h

= 3.14 × 7² × 14

= 2154.04cm³

When the radius and height are reduced to 5cm and 9cm, the volume will be:

= πr²h

= 3.14 × 5² × 9

= 706.5cm³

This illustrates that the volume reduces when the height and radius reduces.

Learn more about volume on:

brainly.com/question/1972490

#SPJ1

8 0

2 years ago

Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

Flauer [41]

Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

Test if less than half of HIV-positive smokers have used a nicotine patch:

At the null hypothesis, we test if the proportion is of at least half, that is:

$H_0: p \geq 0.5$

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

$H_1: p < 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5$

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that $n = 444, X = \frac{202}{444} = 0.455$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}$

$z = -1.9$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

5 0

3 years ago