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3 years ago

15

Which set of angles can be used to construct a triangle? A) 72°, 73°, and 54° B) 88°, 34°, and 58° C) 89°, 46°, and 54° D) 95°,

50°, and 27°

2 answers:

kaheart [24]3 years ago

6 0

B) 88°, 34°, and 58°

Answer:

B) 88°, 34°, and 58°

Step-by-step explanation:

solniwko [45]3 years ago

4 0

Answer:

the answer is b

Step-by-step explanation:

as it needs to add up to 180

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Find the coordinates of the midpoint of a segment with the endpoints (7,−5) and (3,3).

aksik [14]

Answer:

(5, -1)

Step-by-step explanation:

Midpoint = (x1 + x2 ÷ 2) , (y1 + y2 ÷ 2)

MP= (7 + 3 ÷ 2), (-5 + 3 ÷ 2)

= (10÷2), (-2÷2)

=(5), (-1)

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3 years ago

Type the correct answer in each box.

Mariulka [41]

Answer:

$(x-5)^2+(y+4)^2=100$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center and any point that lie on the circle is equal to the radius

we have the points

(5,-4) and (-3,2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$r=\sqrt{(2+4)^{2}+(-3-5)^{2}}$

$r=\sqrt{(6)^{2}+(-8)^{2}}$

$r=\sqrt{100}\ units$

$r=10\ units$

step 2

Find the equation of the circle

we know that

The equation of a circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

we have

$(h,k)=(5,-4)\\r=10\ units$

substitute

$(x-5)^2+(y+4)^2=10^2$

$(x-5)^2+(y+4)^2=100$

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