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tino4ka555 [31]
2 years ago
7

Adult tickets to the faculty-students basketball game sold for $5 each and student ticket was sold for $2 each. if 235 tickets w

ere sold for a total of $725, how many of each kind of ticket were sold?
Mathematics
1 answer:
Serhud [2]2 years ago
8 0

Answer:

85 adult tickets

150 children tickets

Step-by-step explanation:

we can write a system of equations and then use the 'elimination method':

let a = adult tickets

let c = children tickets

a + c = 235

5a + 2c = 725

we can multiply the first equation by -5 to get:

-5a - 5c = -1175

now we can add the second equation to get:

5a + 2c = 725

-3c = -450

c = 150

a + 150 = 235

a = 85

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Given f(x)=8x+13 and g(x)=x^2-5x, find (f-g)x
uysha [10]

(f-g)x= -x²+13x+13

Hope it helps you....

4 0
3 years ago
Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
  • x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4

The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

8 0
2 years ago
Wesimann Co. Issued 13-year bonds a year ago at a coupon rate of 7.3 percent. The bonds make semiannual payments and have a par
Harman [31]

Answer:

Current Bond price = $1155.5116

Step-by-step explanation:

We are given;

Face value; F = $1,000

Coupon payment;C = (7.3% x 1,000)/2 = 36.5 (divided by 2 because of semi annual payments)

Yield to maturity(YTM); r = 5.6%/2 = 2.8% = 0.028 (divided by 2 because of semi annual payments)

Time period;n = 13 x 2 = 26 years (multiplied by 2 because of semi annual payments)

Formula for bond price is;

Bond price = [C × [((1 + r)ⁿ - 1)/(r(r + 1)ⁿ)] + [F/(1 + r)ⁿ]

Plugging in the relevant values, we have;

Bond price = [36.5 × [((1 + 0.028)^(26) - 1)/(0.028(0.028 + 1)^(26))] + [1000/(1 + 0.028)^(26)]

Bond price = (36.5 × 18.2954) + (487.7295)

Bond price = $1155.5116

8 0
3 years ago
What is -4a+1a in addition
Alex

Answer:

-3a

Step-by-step explanation:

Ignore the variable since they are the same, apple and apples, and simply pay attention to the coefficient

8 0
3 years ago
Solve<br> log4 (x+3)- log4 (x+2)≥3/2<br> Please help
mart [117]
Https://web2.0calc.com/ try this or

this http://rational-equations.com/in-rational-equations/graphing-equations/distributive-property-simplif...
they are math calculator..... hope this helps
4 0
3 years ago
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