Question

Select the two values of x that are roots of this equation. 3x-5=2x^2​

Answer 1

Solution:

3x - 5 = -2x²

2x² + 3x - 5 = 0

By splitting the middle term,

2x² - 2x + 5x - 5 = 0

2x (x - 1) + 5 (x - 1) = 0

(2x + 5)(x - 1) = 0

So, 2x + 5 = 0

x = -5/2

(OR)

x - 1 = 0

x = 1

The roots of 2x² + 3x - 5 = 0 are: A. x = 1 & B. x = -5/2

Answer 2

Step-by-step explanation:

$3x - 5 = - {2x}^{2}$

➡

${2x}^{2} + 3x - 5 = 0$

(2x+5)(x-1) = 0

one of these multiple should be 0 so the equation is equal to 0

therefore if 2x + 5 = 0 then

x = -5/2

and if x+1 = 0 then

x = 1