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stepan [7]
2 years ago
13

The volume of a right cylinder is 27π cubic centimeters, and the high is 3 centimeters (cm). What is the radius of the cylinder?

Mathematics
2 answers:
Dmitrij [34]2 years ago
4 0

Answer:

B

Step-by-step explanation:

The volume is the height x area of base, 27pi / 3 = 9pi

Area of base is radius square x pi, 9 pi = 3^2 x pi

vlada-n [284]2 years ago
4 0

Answer:

B

Step-by-step explanation:

The equation for the volume of a cylinder is pi*r^2h.  3*3^2=27, so the radius is 3.

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Find the are of each figure
Umnica [9.8K]

Answer:

I think the figure of N and E of 48in is 2304. The figure of I and E and N and A of 32in is 1024. The figure of L and I and L and A is 144.

Step-by-step explanation:

To find the area, you have to multiply of each side in each figure. For example, Figure A and B and C and D of 16in is 16 × 16 which is 256.

A = Area

a = Side

A = 2304, A = a^2 = 48^2 = 2304.

A = 1024, A = a^2 = 32^2 = 1024.

A = 144, A = a^2 = 12^2 = 144.

I hope this answers your question!

8 0
3 years ago
If an integer m is divisible by both 10 and 12, then it must also be divisible by which of the following?
Murrr4er [49]

Answer:

20

Step-by-step explanation:

an integer m is divisible by both 10 and 12

Lets write the prime factor for each number

the prime factor for 10 is 5,2

the prime factor for 12 is 3,2,2

Now take the product of the  prime factors that are not in common and also in common5 \cdot 3 \cdot 2 \fdot 2= 60

60 is divisible  by 20

so answer is 20

3 0
3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
A bathtub is filling with water at a rate of 60 liters per minute.
Phoenix [80]
60t is your answer

Have a good day
7 0
3 years ago
Factor each Polynomial<br> 3x^2 + 17x + 10
Naddika [18.5K]
3x^2+17x+10\\\\17x=15x+2x\\10=5\cdot2\\\\3x^2+17x+10=3x^2+15x+2x+10\\\\=3x\cdot x+3x\cdot5+2\cdot x+2\cdot5=3x(x+5)+2(x+5)\\\\=\huge\boxed{(x+5)(3x+2)}
8 0
3 years ago
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