Answer:
A
Step-by-step explanation:
Answer:
Hello your question is incomplete attached below is the correct question
and the solution
answer: A
Step-by-step explanation:
attached below is a detailed solution of the given problem
There exists P and C such that ( ∵ λ1 ≠ λ21 so A is diagonalizable )
The expressions for the width, W, and area, A, of the rectangle in terms of L are:
- W =
- L - A =

The expression for the perimeter of a rectangle is given as:
P = 2(L + W)
where L is its length and W its width
a. Given that the perimeter of the rectangle is 13 feet, then;
13 = 2(L + W)
divide through by 2
= L + W
So that;
W =
- L
The required formula for the width as a function of L is: W =
- L
b. Area of a rectangle can be expressed as;
A = L * W
substitute the expression for width in that of area to have
A = L * (
- L)
=
L - 
A = 
The expression for the area A is: A = 
Visit: brainly.com/question/10452031
She brings 3 donuts because a dozen is 12 and 1/4 of 12 is 3.
Answer:
50%
Step-by-step explanation:
3450 - 2300 = 1150
1150/ 2300 × 100 = 50