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2 years ago

What’s the difference between an inscribed and circumscribed circle

2 answers:

6 0

A circumscribed figure is a shape drawn outside another shape. For a polygon to be inscribed inside a circle, all of its corners, also known as vertices, must touch the circle. If any vertex fails to touch the circle, then it's not an inscribed shape

kykrilka [37]2 years ago

5 0

Inscribed is a polygon inside a circle with all points on a given point in the circle. Circumscribed is a circle inside a polygon with any given point touching just one point on the polygon. Hope this helped.

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Find the unit rate. A 6oz jar of jalapeños cost $2.34

Levart [38]

Answer:

1oz cost $0.39 which will be the unite rate

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

0.3, 0.08, 0.003, 0.83<br> In order from smallest to largest

pishuonlain [190]

0.003, 0.08, 0.3, 0.83

3 0

2 years ago

Read 2 more answers

Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B

jeka94

$\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0$

$M_y=35x^4+14x^5-6y^2-12xy^2$
$N_x=35x^4-6y^2$

$\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2$

This suggests an integrating factor depending on $x$ only is possible, and given by

$\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}$

Distributing across the ODE, we end up with

$\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0$

The equation is now exact, with

${M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}$

Now we find the solution:

$F_x=M^*$
$F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx$
$F=(7x^5y-2xy^3)e^{2x}+f(y)$

$F_y=N^*$
$(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}$
$f'(y)=0$
$\implies f(y)=C$

The general solution is then

$F(x,y)=(7x^5y-2xy^3)e^{2x}=C$

7 0

3 years ago

2/3x - 11 = x/3 + 3

Grace [21]

2
3

−
1
1
=

3
+
3
2
3
x
−
11
=
x
3
+
3
32x−11=3x+3
2

3
−
1
1
=

3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
Find common denominator
2

3
−
1
1
=

3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2

3
+
3
(
−
1
1
)
3
=

3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
3
Combine fractions with common denominator
2

3
+
3
(
−
1
1
)
3
=

3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
2

+
3
(
−
1
1
)
3
=

3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
4
Multiply the numbers
2

+
3
(
−
1
1
)
3
=

3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
2

−
3
3
3
=

3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
5
Find common denominator
2

−
3
3
3
=

3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
2

−
3
3
3
=

3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
6
Combine fractions with common denominator
2

−
3
3
3
=

3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
2

−
3
3
3
=

+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
7
Multiply the numbers
2

−
3
3
3
=

+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
2

−
3
3
3
=

+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
8
Multiply all terms by the same value to eliminate fraction denominators
2

−
3
3
3
=

+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
3
⋅
2

−
3
3
3
=
3
(

+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
9
Cancel multiplied terms that are in the denominator
3
⋅
2

−
3
3
3
=
3
(

+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
2

−
3
3
=

+
9
2
x
−
33
=
x
+
9
2x−33=x+9
10
Add
3
3
33
33
to both sides of the equation
2

−
3
3
=

+
9
2
x
−
33
=
x
+
9
2x−33=x+9
2

−
3
3
+
3
3
=

+
9
+
3
3
2
x
−
33
+
33
=
x
+
9
+
33
2x−33+33=x+9+33
11
Simplify
Add the numbers
Add the numbers
2

=

+
4
2
2
x
=
x
+
42
2x=x+42
12
Subtract

x
x
from both sides of the equation
2

=

+
4
2
2
x
=
x
+
42
2x=x+42
2

−

=

+
4
2
−

2
x
−
x
=
x
+
42
−
x
2x−x=x+42−x
13
Simplify
Combine like terms
Multiply by 1
Combine like terms

=
4
2
x

5 0

2 years ago

Noah spent $66 for 20 gallons of gasoline. Lydia spent $81.25 for 25 gallons of gasoline. How much did each person spend for 1 g

Morgarella [4.7K]

Answer:

Noah spent $3.3 for 1 gallon of gasoline.

Lydia spent $3.25 for 1 gallon of gasoline.

Step-by-step explanation:

To find how much each person spent for 1 gallon of gasoline, we divide the amount spent by the number of gallons.

Noah spent $66 for 20 gallons of gasoline.

Amount spent $66, 20 gallons. So

66/20 = $3.3

Noah spent $3.3 for 1 gallon of gasoline.

Lydia spent $81.25 for 25 gallons of gasoline.

Amount spent $81.25, 25 gallons. So

81.25/25 = $3.25

Lydia spent $3.25 for 1 gallon of gasoline.

7 0

2 years ago