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Aleks [24]
2 years ago
14

Julie’s mom paid $2.70 for 5 pounds of bananas at Supermart. Mario’s mom paid $2.60 for 4 pounds of Bananas at Market One. Write

a division equation for each banana purchase, and then decide which store had the better banana price.
thx :D
Mathematics
2 answers:
serg [7]2 years ago
7 0

Answer: (Supermart) Equation 1 = $2.70÷5 lb = $0.54 per lb

(Market One) Equation 2 = $2.60÷4 lb = $0.65 per lb

Since the unit price of bananas per lb in Supermart is less than the unit price of bananas per lb in Market One, Supermart has the better price.

skad [1K]2 years ago
7 0

Answer:

Market One

Step-by-step explanation:

Market one charges about $1.54 per pound and Supermart charges $1.85 per pound

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A balloon is blowing up at a constant rate of 9 cubic centimeters per second. When the volume of the balloon is 2048/3 pi cubic
jekas [21]

Answer:

\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec

Step-by-step explanation:

<u>Rates of Change as Derivatives</u>

If some variable V is a function of another variable r, we can compute the rate of change of one with respect to the other as the first derivative of V, or

\displaystyle V'=\frac{dV}{dr}

The volume of a sphere of radius r is

\displaystyle V=\frac{4}{3}\pi r^3

The volume of the balloon is growing at a rate of 9\ cm^3/sec. This can be written as

\displaystyle \frac{dV}{dt}=9

We need to compute the rate of change of the radius. Note that both the volume and the radius are functions of time, so we need to use the chain rule. Differentiating the volume with respect to t, we get

\displaystyle \frac{dV}{dt}=\displaystyle \frac{dV}{dr}\displaystyle \frac{dr}{dt}

\displaystyle \frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}

solving for \displaystyle \frac{dr}{dt}

\displaystyle \frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2}

We need to find the value of r, which can be obtained by using the condition that in that exact time

\displaystyle V=\frac{2048}{3}\pi\ cm^3

\displaystyle \frac{2048}{3}\pi=\frac{4}{3}\pi r^3

Simplifying and isolating r

\displaystyle r^3=512

\displaystyle r=\sqrt[3]{512}=8\ cm

Replacing in the rate of change

\displaystyle \frac{dr}{dt}=\frac{9}{4\pi 8^2}

\displaystyle \frac{dr}{dt}=\frac{9}{256\pi }

\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec

8 0
3 years ago
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