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Softa [21]
2 years ago
9

When solving a mass to mass problem, what is the first thing you do after balancing the equation?

Chemistry
1 answer:
Brrunno [24]2 years ago
5 0

Answer:

the answer is c

Explanation:

because when I had my test it was correct

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Using solubility guidelines, predict whether each of the following compounds is soluble or insoluble in water.
seraphim [82]
<span>1. MgBr2

Soluble.

Rule: all the binary compounds of the group 17 (different to F) with metals are solubles, except those formed with Ag, Hg (I) and Pb.

2. PbI2

Insoluble.

Rule: it is one of the exceptions stated in the rule above.

3. (NH4)2CO3

Soluble.

Rule: salts containing NH4(+) are soluble.

4. ZnSO4

Soluble

Rule: </span><span>This salt is not an exception to the rule that most sulfate salts are soluble. Important exceptions to this rule include BaSO4, PbSO4, Ag2SO4 and SrSO4

5. Sr(OH)2

Soluble (slightly soluble).

Rule: </span><span>Hydroxide salts of Group II elements (Ca, Sr, and Ba) are slightly soluble</span>
6 0
3 years ago
Read 2 more answers
We dissolve 2.45 g of sugar in 200.0 g water. what is the mass percent of sugar in the solution?
LiRa [457]

 The  mass percent  of  sugar  in the   solution is 1.225%


      <u><em>calculation</em></u>

mass percent =  [(mass  of solute /mass  of solution ) x  100]

mass   of  solute (  mass of a substance that  dissolve in another substance)

   = 2.45 g

mass  of  solution( mass of a  substance that dissolves  a solute) =200.0 g


Therefore mass  percent = 2.45 g/200.0 g  x 100 = 1.225% of sugar in solution

8 0
3 years ago
Read 2 more answers
Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta
Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = R=\frac{8.24 mL}{t}

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = R'=\frac{3.86 mL}{t}

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{R}{R'}=\sqrt{\frac{M}{32 g/mol}}

\frac{\frac{8.24 mL}{t}}{\frac{3.86 mL}{t}}=\sqrt{\frac{M}{32 g/mol}}

M=\frac{32 g/mol\times 8.24 \times 8.24}{3.86\times 3.86}=145.82 g/mol

4 0
3 years ago
What is the whole mass of air surrounding earth?
irinina [24]
It is 50 or 50% mass and air . Average Stone weight in Earth.
5 0
3 years ago
3 The weight of an atom is determined primarily by —
enot [183]

Answer:

A)The total number of protons plus neutrons= Weight of an atom

7 0
3 years ago
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